Recent content by anonymous820

thank you

Homework Statement how do you convert watts into ohms? Homework Equations The Attempt at a Solution

thanks

Homework Statement if its 26.6 milliamps and you want amps is it .026 or .0026? Homework Equations The Attempt at a Solution

what does the E stand for? current?

nope. that's why i can't figure out anything besides the resistance. i don't even think the question has possible answer.

Homework Statement R=resistor determine the voltage across and the current through each resistor for the circuit. The Attempt at a Solution 1&2=parallel 1/50+1/25=3/50 --> 50/3=16.7 ohms 3&4=parallel 1/10+1/10=1/5 --> 5 ohms 5&6=series 5+10=15 ohms total resistance=36.7...

Homework Statement A ball of mass .5 kg is attached to the end of a cord whose length is 1.5 m. The ball is whirled in a horizontal circle. If the cord can withstand a maximum tension of 50 N, what is the angular speed the ball can have before the cord breaks? Homework Equations...

less. so IT IS divide. thanks. i knew 400,000 hp was unreasonable for a person. this was a lab btw.

Homework Statement how do u get from power to horsepower? mass=60 kg weight=588.6 N height=7 m time=6.45 s power= 638.79 W Homework Equations ---- The Attempt at a Solution multiply by 746 W to get: 476537.34 hp or divide by 746 W to get: .856286 hp i think its divide...

Homework Statement water flows over a section of niagara falls at the rate of 1.2*10^6 kg/s (kilograms per second) and falls 50.0 m (meters). How much power is generated by the falling water? Homework Equations --none. The Attempt at a Solution gravitational potential energy...

oh okay. so i pretty much already found c from question b. alright. thank you.

there was no point in b. that was the dumbest question possible. I am so slow. its in equilibrium, so therefore, the sum of all the forces is 0, duh. wow. lol. yet. but i will be soon =) i don't quite understand what I am doing for question c. 211 N?

oh yeah. and is d. right? i found the coefficient the same way i found the cofficient in the other problem about the skiing. except this time, they actually gave me real numbers i could work with.

it tells you that the normal force and the Fy are equal to 325 N? then, the applied force is negative and Ff and Fx are negative? so then, Fx and the applied are equal? or Fx and Ff are equal? or Fx and Ff are equal to the applied? lol. ..no problem. i figured it was a much better set up...