Not sure I never use KCL/KVL anymore lol.
If you know how to use node analysis you can get the answer more quickly and easily.
Establish a node as ground and the voltage at the node you want to solve you just sum the currents into that node to zero.
Establishing the right node as ground...
don't know if that helps.
Solution:
Yeah so I just changed to complex impedances (C = 1/sC) and used node analysis and with enough algebra I managed to manipulate the correct equation.
You just set vx=0 since it's connected to ground.
Homework Statement
This is a twin-T notch filter.
[PLAIN]http://l23.sphotos.l3.fbcdn.net/hphotos-l3-snc4/hs1360.snc4/163224_10150132441064992_712009991_8008832_7339032_n.jpg Homework Equations
R = R
C = 1/sC
L = sL
The Attempt at a Solution
Not sure if my complex impedance equations are...
Thevenin circuit is a resistor and voltage source in series.
To reduce the circuit to a thevenin equivalent circuit you would replace all the resistances between a and b with one equivalent resistor and reduce the voltage sources to one source.
think of two parallel resistors being...
Thanks for the help but I've managed to solve it correctly.
You use sinusoidal steady state to find the parasitic R in the inductor. The R attached in the circuit is not the parasitic R. It's just a regular resistor. There's also some unknown parasitic resistance in the non-ideal inductor...
Hmm. Well in class we were taught to use sinusoidal steady states to solve these problems which is where the relevant equations came from.
Using your method I get I=IL=(jwL+50)/(2costwt)
Then solving for VL in V=IZ I get
VL = (-w2L2+50jwL) / 2coswt
However I'm not sure what to do...
Homework Statement
[PLAIN]http://sphotos.ak.fbcdn.net/hphotos-ak-snc4/hs894.snc4/72731_10150110340044992_712009991_7710053_709779_n.jpg
The circuit has a non-ideal inductor with parasitic R. v0(t) goes to coswt as the limit of w goes to zero.
The output signal has a +15 degree phase...
Are the three bulbs the only resistances in the circuit?
Then all you would have to do is find the total resistance of the lightbulbs which I believe you did. The two in series and then that in parallel with the other bulb should be the total resistance assuming the battery's resistance to be...
Ah thanks for the reply. Current taking the path of least resistance? I've been told not to believe it as it's not actually true but maybe that pertains to real life and not ideal circuits for problems i guess. Anyway thanks again!
Homework Statement
I want to find ix in the circuit below when the switch opens at t=0 after having been closed for a long time.Homework Equations
v(t) = v(infinity) + (v(0)-v(infinity))e-t/RC
i(t) = C dv(t)/dt
ix = isource - i(t)
v(t) = voltage across capacitor
i(t) = current through...