Recent content by Apple&Orange

Edit: Never mind guys, figured it out. I needed to use s.equals :) However, could someone explain to me why we can't use == on a technical level? I'm curious to know on a technical level. Hi guys Doing a bit of programming, and I'm not too sure why I'm not getting the expected results. Below...

Hi guys, I've had another thought. Assuming same actuator specifications, which of the three scenarios would draw more current from the actuators? Based on my understanding of basic physics, I am inclined to say Scenario B, mainly because the vertical force component of the actuator relative...

So the 200lbs actuator should draw less current then, given it has a higher gearing? The actuators will need to lift around 105Kg of vertical load. However, I have both of them opening at an angle of 27.72 given the design constraints. The power of the motor is seems correct, because that is...

G'day guys So I currently have a 2x 8" stoke 150lbs dynamic force actuators with a maximum current draw of 5A. The exact one is the FA-PO-150-12-XX in the link below: https://www.firgelliauto.com/products/feedback-rod-actuator The load I have on it causes the actuators to draw almost its'...

Thanks for your responses guys, and apologies; I should've been a bit more clearly on what I'm trying to achieve. This test was to investigate how much variation there is in terms of the force that is needed to overcome the total friction in the hinges that we stock. The method of investigating...

Thanks, that was what I was looking for. I have a few samples of these hinges to do the test, so I hope this will help with the accuracy. Just for final confirmation, would I still use the formula Fs = μsN, in this situation? From what I found out, the above formula is used in a lot of linear...

Hi guys I'm looking to calculate the static frictional force for a hinge Below is a CAD image of the component I am testing. I am thinking of attaching a hook onto the plate as shown below, and continuously add weights at the end of the hook until the hinge begins to move. By multiplying...

Hey Nidum Thanks for the feedback. Just so I am on the right track... From a practical point of view, it would be best to have the actuator closer to the hinge the as shown below? I am guessing this is more practical for the following reasons: Less intrusive for people to load things at the...

Thanks Nidum Would the best place to push the lid be at the very end of the lid? As for the angle, would the ideal place be perpendicular to the surface of the lid?

Homework Statement [/B] Superman must stop a 120-km/hr train in 150 m to keep it from hitting a stalled car on the tracks. If the trains mass is 3.6 x 10^5 kg, how much force must he exert? Vi = 33 m/s (120 km/h) Vf = 0 m/s Displacement (Xf - Xi) = 150 m M = 3.6 x 10^5 kg Homework Equations...

Hi everyone! So I'm working on project where I have to design a hinge system for a hard lid that is fitted onto the back of a pickup truck. In this system, I will be using 2x linear actuator(s) that will need to lift a total weight of roughly 95kg. At the moment, I've got a selection of 600N...

Homework Statement Please see questions (c) and (e) on the attachement 2.Relevant Equations The Attempt at a Solution So long story short, these two questions were given out as a challenge in one of our Swedish lessons to see if we could remember our high school calculus, which I shamefully...

Thanks Simon and jedishrfu. It turns out it was the wrong calculation in (2) as you guys spotted. Need to triple check my work next time :smile:

Homework Statement Homework EquationsThe Attempt at a Solution I can't remember what this method of calculation this is as it's been a while since I've done this. [/B] Could someone explain to me what I've done wrong in my calculations? The answer was 13.8N at 80 degrees.

Homework Statement Homework Equations Torque = F x D Manticlockwise = Mclockwise The Attempt at a Solution From what I understand, the moment on left hand side of the pivot point needs to be equal to the moment on right hand side, therefore... (Fx.2)+(5x.14) = (7xd) My initial...