I've gotten interested in this pair production stuff, and I'm wondering: Why is it that some nuclei can absorb more energy than the energy needed for pair production, while other nuclei result with the incoming energy creating pair production? Is it because heavier nuclei can distribute the...
Mike, you're awesome. Thank you for finally bringing my curiosity to a close. I stumbled across NMR and was left puzzled by the explanations on the internet. They seemed to suggest that only isotopes could be utilized for NMR. Also, I was curious about the relationships between the...
Sorry to test your patience, but: Bottom line is non-isotope Copper (Copper as found on the periodic chart) is NMR active?
I'm going off the image of the proton, neutron, and electron configuration on this page: http://www.historyforkids.org/scienceforkids/chemistry/atoms/copper.htm"
Oh...
Now I am trying to figure out if NMR can be used to heat atoms that are not isotopes. (To my understanding, an isotope is an atom that has a different number of neutrons than the atom as it appears on the periodic chart). I know the wikipedia page on NMR says the atoms have to be isotopes, but...
So the 1/r^3 equation is no good? That guy has a PhD. If 1/r^3 is correct, then would someone please tell me whether it's in Gauss or Tesla? Also, how far is "magnetostatic field far away from the sources (permanent magnets or currents)"? And I am assuming r is in meters?
Gracias once again
First of all, thank you. Second, on the Wikipedia page, I don't see the equation you provided; is the strength of a magnetic field really as simple as just multiplying the magnetic field at the source by 1 divided by the cube of the distance you are from the magnet? Also, what are the units...
I am trying to find an equation that tells the strength of a magnetic field a given distance away from the source. It would be very helpful if all terms are defined, since the internet is notorious for not saying what variables mean.
Gracias
Hmm... I think I figured it out: The magnetic and EM fields applied are directly proportional to each other, and they are also directly proportional to the heat generated. I got this from the bottom of the following page:
http://hyperphysics.phy-astr.gsu.edu/hbase/nuclear/nmr.html#c1
It...