Recent content by BadSkittles

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    The gravitational field g due to a point

    I think its m = M ( r^3/ R^3)
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    The gravitational field g due to a point

    So the gaussian surface is 4 pi r^2 still, but the mass is a ratio between V and m?
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    The gravitational field g due to a point

    ∫ dA is your gaussian surface. Would that be 4/3 pi r^3 ? Since our radius is shortened. M is the Mass of the whole planet.
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    The gravitational field g due to a point

    I got g * Integral of dA = -4*pi G*M g * 4 * pi * r^2= -4* pi* G*M g= - GM/ r^2 Maybe the integral of dA is something else?
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    The gravitational field g due to a point

    I tried to divide the mass by 2, and the answer is still wrong. Do you know any way to solve this problem T-T
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    The gravitational field g due to a point

    does that mean i would have to take a fraction of the mass, because of the radius?
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    The gravitational field g due to a point

    The gravitational field g due to a point mass M may be obtained by analogy with the electric field by writing an expression for the gravitational force on a test mass, and dividing by the magnitude of the test mass, m. Show that Gauss' law for the gravitational field reads: phi = oint...
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    Two infinite sheets with charges

    sorry, solved... direction mattered
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    Two infinite sheets with charges

    I got 880957 N/C as my answer
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    Two infinite sheets with charges

    Wouldn't you just add the absolute value of both electric fields since the electric fields from both of the plates are headed towards the same direction?
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    Two infinite sheets with charges

    Two infinite-plane non-conducting, thin sheets of uniform surface charge p1 = 12.30 uC/m2 and p2 = -3.30 uC/m2) are parallel to each other and d = 0.615 m apart. What is the electric field between the sheets? (Note: the field is positive if it is parallel to the vector x). Hi, I've tried this...
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    Is the Magnitude of an Electric Field Consistent Across All Spatial Locations?

    Hello, in an electric field, are the magnitudes of the field the same regardless of the spatial location? Or is the field's magnitude similar to the force experienced by the test charge where it gets smaller as you move away from the source charge? Any clarification would be appreciated.
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    Gravitational Weight into kilograms

    Isnt Weight = mass * gravity of earth so 1 kilogram = 1 lb? Or am i missing something
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    How do different forces affect the acceleration of a spinning uniform disk?

    Hello, can someone explain to me what is the difference between center mass acceleration and angular acceleration? If i have an uniform disk laying still, then i give it a force to make it spin while it stays put. The angular acceleration obviously has a number. What about the acceleration of...
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    Angular velocity, acceleration, and torque

    a merry go around like circle
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