Recent content by bakra904

so basically v. \nabla\psi = 0 which proves that v and \nabla\psi are perpendicular (since their dot product is 0) and so \psi must be tangent to v

oh right...i overlooked that part. thanks!

Thanks a bunch! I'm a new poster and did not know about the effort rule...I had worked on it but did not post what I had worked on. I was trying to use the fact that if v = \nabla \times \psi, then that would imply that \psi is a stream function, which in cartesian co-ordinates would...

Proof: Everywhere Tangent to Curve?? If the function v depends on x and y, v(x,y) and we know there exists some function psi(x,y) such that v[SIZE="1"]x = partial w.r.t (y) of psi v[SIZE="1"]y= -(partial w.r.t (x) of psi) show that the curves psi(x,y) = constant, are everywhere tangent to v.

Fluid Dynamics Question about streamlines...help!? If the velocity field, v, of a fluid depends on x and y, v(x,y) and we know there exists some function psi(x,y) such that v[SIZE="1"]x= partial w.r.t (y) of psi v[SIZE="1"]y = -(partial w.r.t (x) of psi) show that the curves psi(x,y) =...