Recent content by beibixx

The more I look at it, the more I think it wasn't supposed to be a Hydrogen atom. But I tried this. Does it make sense? The original problem: 1. The diagram above shows the lowest four discrete energy levels of an atom. An electron in the n=4 state makes a transition to the n=2 state...

Right..so to do this again. For part a) In order to find the energy level I use the equation E = (hc/lambda), with the given wavelength being 121.9nm and hc = 1.24 x 10^3eV*nm So E = [(121.9nm)/1.24 x 10^3eV*nm)] E=10.1723 For part b) E=pc, where p is momentum Rearranging this I...

sorry I re posted this and thought I could delete the old post but I have no idea how to do it...

Let me know where my logic is off...Much thanks! so a) For T1: Transition -54.4-(-13.6) = 40.8 eV For T2: -13.6 - (-6.04) = 7.56 eV T3=? n4 = n3 so -6.04 + 7.56 = 1.52 eV T3 = 1.52 eV n4 = 1.52 eV b) E = pc c = 6.63 x 10^-34 JS p = E/c p = 1.52/ 6.63 x 10^-34 JS p=2.29 x 10^33 c) KEmax =...

I'm guessing this is wrong..

Thanks for the welcome! So after doing this I read the "energy levels not drawn to scale" and have a feeling that my assumption was wrong, but hey, you never know... so a) For T1: Transition -54.4-(-13.6) = 40.8 eV For T2: -13.6 - (-6.04) = 7.56 eV T3=? n4 = n3 so -6.04 + 7.56 = 1.52 eV T3...

1. The distance between two slits is 0.0500 nm and the distance to the screen is 2.50 m. What is the spacing between the central bright fringe and the first-order fringe? Use yellow light with a wavelength of 580.0 nm. Answers: a. 0.010m b. 0.029m c. 0.290m d. 0.10m e. 0.6m 2. y =LtanΘ...

1. The diagram above shows the lowest four discrete energy levels of an atom. An electron in the n=4 state makes a transition to the n=2 state, emitting a photon of wavelength 121.9 nm (a)Calculate the energy level of the n=4 state. (b)Calbulate the momentum of the photon. The photon is then...