Recent content by beneakin

[H+] = 10^[-6.55] = 2.8*10^-7 = [OH-] since it is pure water? so keq= [2.8*10^-7]^2 = 7.94*10^-14 ΔG°=-(8.31450)(273+50)ln(7.94*10^-14) = 81.00 KJ mol- is that correct, are we sure that it is in an equilbrium at 50C? thanks again

Homework Statement The pH of pure water is temperature dependent, for example it is 6.55 at 50 C. Determine ΔG° for the ionization of water at 50C Homework Equations ΔG=ΔG°+RTln(Q) at eqm ΔG=0 q=Keq pure water: pH 7.00 at 25C The Attempt at a Solution Not sure if the process...

how do i find X

Homework Statement What is the capor pressure of a solution containing .15 mol of glucose (C6H12O6) and 1.65 mol of water at a temperature of 60.0C? the vapor pressure of pure water at this temperature is 149.38 torr Homework Equations Ralout's law? P=PoX The Attempt at a...

great thanks so much

is that the final answer? it seems a bit large to be? thanks

Homework Statement Find the derivative: ( (X^3-1)/(X^3+1) )^1/3 Homework Equations d/dx f(g(x)) = f'(g(x)) * g'(x) quotient rule x/a x'a-xa'/a^2 The Attempt at a Solution first i used the chain rule and quotient rule to get 1/3 ((x^3-1)/(x^3+1))^-2/3 * ((3x^2(x^3+1) -...

ahh so then (2*1)^4 = 16 thanks a lot

Homework Statement Find the limit or prove it does not exist. lim as s->0 (sin2s)^4/s^4 Homework Equations i know i have to use sinx/x = 1 but I am having trouble manipulating the function into that form The Attempt at a Solution my first thought was that i could just take...

wow.. i must have done something wrong in that calculation ...just got what i think is the answer first try.. here's what happened... (x-x+h)/((x+h)x) h / x(x+h) then times that by 1/h from the beginning of the problem to get h / h(x^2+h) which is 1 / x^2 Is this right...

I've been working on this one for a while now but just can't figure it out lim h->0 (1/h) (( 1 / (x + h) ) - ( 1 / x )) my first thought was to figure out (( 1 / (x + h) ) - ( 1 / x )) first by just putting them togeather and then using the congjigate times by one trick but that just...

im sorry i just wanted to see if the equations would show up properly as I am still tryna figure out this problem i found in the archives

1. Homework Statement http://www.nellilevental.com/calc1.jpg 2. Homework Equations C1 = \left(x - 1\right) ^{2} + y^{2} = 1 C2 = x^{2} + y^{2} = r^{2} 3. The Attempt at a Solution Initially I thought that the "value" of R was just going to increase without bound since the...