What is the limit of (sin2s)^4/s^4 as s approaches 0?

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Homework Statement


Find the limit or prove it does not exist.

lim as s->0 (sin2s)^4/s^4


Homework Equations


i know i have to use sinx/x = 1 but I am having trouble manipulating the function into that form


The Attempt at a Solution



my first thought was that i could just take the 2 out as a constant would that just be (2^4)(sinx)^4/x^4

but then i have (sinx)^4 not sinX^4 I am stuck on what king of algebra will work here
 
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a^2/b^2=(a/b)^2
 
Lim_(x->0) of sin(ax)/(ax)=1
 
ahh so then (2*1)^4 = 16

thanks alot
 
beneakin said:
ahh so then (2*1)^4 = 16

thanks alot
good, welcome!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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