Recent content by bigman8424

anyone want to check my work, i would greatly appreciate it: the quest. asks you to find law of mass attraction to calculate force of gravational of Jupiter towards sun: used formula: F = GMm/R2 = (6.67e-11)(1.99e30)(1.90e27)/(7.78e6)2 FJupiter = 4.17e33 Newtons ?? Then it asks...

an object mass of .5kb revovles uniformly in cirlce horizontal frictionless surface. it is attached by .75 m cord to pin set in surface. if object makes 2 complete revolujtions per second, find its speed and its centripetal force mg = m(v2/r) gr = v2 v = sq root of gr v = sq root of...

how does this look, fun prob., need help on the 2nd part: wat is the force that a 60 kb girl has on a 75 kg man, when they are 50 cm apart: f = GM1m2/R2 = F = (6.67e-11)(75)(60)/(.50)^2 = 1.2e-6 N second part: how fast will man accelerate towards girl?? same formala?

a = 9.8 ??

object thrown up with initial velocity of 15 m/s and horizontal velocity of 18 m/s, how much time is required to reach the highest point of trajectory? Vox = 18 y = yo + vosint + 1/2gt^2

so, is the new equation: f(-1)(1) = (1/2)(0.5)(4)^2 + 0 - (0.5)(9.8)(1) ?? ans: 900 J ?

looks like a fun problem, just got to understand it: A 500g block slides down a radial track with height of 1.0 m, it's radius is 1.0 m, with velocity of 4 m/s at the end of the track. what is the loss of the TME? Disipation of energy problem: TMEf - TMEo F * D = K.E.f + P.E.f - (K.E.o...

Oh i see, if the scale read zero, then he's free falling. ?

sounds fun is anyone good in elevator problems, I'm having trouble on a different problem, i need to find the acceleratin of a 600 n man on a bathroom scale in an elevator. once it starts moving, it reads 900 n i posted the question on https://www.physicsforums.com/showthread.php?t=79172...

kinetic friction?? but, if the coefficient of kinetic friction was .20, then i would use my original formula: (15.00)(9.8)(0.60) - Fk = MA (15.00)(9.8)(0.60) - 0.20 = (15.00)A

Ef = wt * sin(37) = ma Ef = mgsin(37) = ma (15.00)(9.8)(0.6) = (15.00)A A = 5.9 m/s^2 ?

a 70.0 kb man climbs vertical rope attached to ceiling. weight of rope is neglected. calculate tension in rope, if accelerate up rope at 0.40 m/s^2 T = m(g+a) T = 70.0(9.8+.4) = 714 N slides downward acceleration of .40 T = m(g-a) t = 70.0(9.8-.4) = 685 N looks good?

please confirm 24000/16000 -9.8 = 5.2 m/s2 please confirm 24000/16000 -9.8 = 5.2 m/s2

a elevator with very worn cables has mass of 1600 kb, cables can withstand max tension of 24000 N, what is max upward acceleration if the cables are not to break please confirm my answer to be amax = 24000/16000 -9.8 = 5.2 m/s2

a 15.00 kb block slides down an included plane at 37.0 degrees to horizontal. find acceleration of block, if plane is frictionless: theta: 37 m = 15.00 kg a = ?? wtx - fk = ma wtcos(53) - Fk = ma 15.00*9.8*.60 - Fk = ma 88 - Fk = ma not sure here n = mgcos37 n = 15.00*9.8*.80...