Recent content by Bizkit

I have a quick question to ask you guys. In the first problem found http://whites.sdsmt.edu/classes/ee382/homework/382Homework4.pdf" , does the vertical line with the subscript x = 0 mean that the x-component of the vector is always 0? If so, then I could just remove the x-component from the...

Thanks for the reply. I'm pretty sure I understand what to do now.

Homework Statement The problem can be found http://whites.sdsmt.edu/classes/ee382/homework/382Homework1.pdf" (the last one), along with a picture of the circuit. Homework Equations R = l/(µS) mmf = NI = ΨR B = Ψ/S The Attempt at a Solution I've never done a problem like this...

That's what my book shows. Perhaps the author made a mistake. As for my earlier question; I'll just ask my teacher about it right before the test, which is coming up really soon here. Thanks anyways.

Sorry for confusing you, I'll try to explain it better. The book I am using is a junior electromagnetics book. It states that the Biot-Savart Law is: \vec{H} = \int_{L}\frac{I d\vec{l} \times \hat{a}_R}{4\pi R^{2}} This equation is for straight conductors. There are two other ones for surfaces...

When finding the angles for the finite length Biot-Savart formula of a filamentary conductor H = I*(cos(α2) - cos(α1))aΦ/(4πρ), is α1 supposed to be calculated at the start of the current, and α2 at the end? I'm just wondering because my book does it this way and vice-versa, so I'm not entirely...

I hate to say this, but I'm still completely in the dark. I know that this problem is probably really easy, and the answer is staring me right in the face, but I just don't get. I must have drank some stupid juice or something. I'm getting really frustrated. If you could just tell me how to...

If you mean the pressure of the first two tanks combined, I can find that. I'll just use the same equation I used before, except I'll insert the correct mass for tank 1. P1-2 = (mtank1+mtank2)*R*T1-2/(Vtank1+Vtank2) = (12.73+8.25)*.287*(25+273)/(1.5+3.02) = 20.98*.287*298/4.52 = 396.98 kPa

I'm not necessarily intimidated by it, I'm just frustrated that I don't know what to do because it seems as though it should be really easy to figure out. It is the specific ideal gas law that I am using. It is in terms of mass, not moles, and R is the specific gas constant (which is different...

Here's what I have: Vtank2 = [mRT/P]tank2 = 8.25*.287*(65+273)/265 = 2.36775*338/265 = 800.3/265 = 3.02 m3 P1-2 = (mtank1+mtank2)*R*T1-2/(Vtank1+Vtank2) = (4.5+8.25)*.287*(25+273)/(1.5+3.02) = 12.75*.287*298/4.52 = 241.25 kPa Is this right so far? If it is, I'm not sure what to do next...

That is trivial. I was thinking that might be the answer, but it just seemed too easy. Anyway, as for what you said about equilibrium pressure, that's actually the next part of the question. I didn't post it because I wanted to take one step at a time. The question is: If a 2 m3 tank was...

So, am I correct, then, in saying that I can ignore the surroundings due to the Zeroth Law of Thermodynamics? Do the surroundings make a difference in the calculation?

I know that when two substances are said to be in thermal equilibrium, they must have the same temperature. I also know that, by the Zeroth Law of Thermodynamics, if two substances are in thermal equilibrium with another substance, then those two substances are in thermal equilibrium with...

Homework Statement A 1.5 m3 tank containing air at 35°C and 750 kPa is connected by a valve to another tank containing 8.25 kg of air at 65°C and 265 kPa. Now the valve is opened and the entire system is allowed to reach thermal equilibrium with the surroundings, which is at 25°C. Determine...

Ok, I understand what you are saying, but I just thought of something else. If the people who wrote the problem wanted me to just define the power as a function of V, then why didn't they just ask me to find the power over a range of wind speeds, without giving any specific values. Since they...