Recent content by BlackWyvern

Sadly I do not. :P I'm not too worried about an actual solution, but more how to find it. Recently I became aware of using Euler's equation to solve rational trigonometric integrals, but I have little practice. Maybe I can use this to turn the equation into something that will integrate by...

Homework Statement What would be the best method to approach this integral? And then solve it. \int\frac{dx}{(sin[x]+2)^2} At first, I thought it would yield to the substitution of u = sin[x] + 2, with du = cos[x]. But this doesn't completely change the integral to one of u. Now, I don't...

bump. <_<

Homework Statement What would the electrical resistance of a paraboloid from y = 0 to L be? Homework Equations R = \rho \frac{L}{A} The Attempt at a Solution Okay, so I'll put the parabola (that would rotate into the paraboloid) into the form y = \sqrt{x} The function A(x) is...

For the parabola example then, how would you do it?

I think I'm right when I say that the centroid of a 2D shape is found by the intersection of the lines that separate that shape into two shapes of equal areas. Is that correct? I don't want to (for now) think about it in terms of moments and integrals, because frankly, it's a little confusing...

I have also done a bit of fiddling around with this. What else you will find very interesting, is that if you inscribe a square, into that circle that is inside the first square, the area of the smaller square is half the area of the larger square. This pattern keeps repeating whichever way you...

Volume of the ice cube, if it's density were equal to that of water, which it almost is. Then refer back to the question with your new information, and you can solve it.

mgh = (0.5)mv^2 If you examine the kinetic energy equation, which says that the energy at the height, will have turned entirely into kinetic energy at the bottom of the fall, you will notice that both sides have mass, it's the same mass, so you can eliminate it as a variable. Always look for...

Density = mass/volume You should know the density of water. The density of ice is more, but using the density of water should be alright here. Unless they've given you it's density.

Part of Bernoulli's Principle is that the mass that leaves the pipe, must be the same as the mass that enters the pipe.

The buoyant force is equal to the weight of the water that is displaced. If we look at the first problem, we can see that it's in equilibrium, which means all the forces are equal. Should be easy to solve the first one now. The second one, I think you have to assume that the ice's density is...

Probably your best bet would be Bernoulli's equation to find the energy before the fluid's transfer of energy, and then find the energy after, and just find the rate. http://en.wikipedia.org/wiki/Bernoulli%27s_principle

Question 13: Kicked his ass. No pun intended, honestly.

1565 x 1200 - (1565 x 3) = ? 4 x 1565 = 6000 + 240 + 20 = 6260 6260 x 300 - (1565 x 3) = ? 6260 x 3 = 18000 + 600 + 180 = 18780 18780 x 100 = 1878000 - (1565 x 3) 1565 x 3 = 4500 + 180 + 15 = 4695 1878000 - 4695 = ? =1873305 This is one way, and it's probably not the fastest, but it uses an...