Recent content by BlasterV

Ok using just the three nodes I cameup with 3 equations: i1 = i2 + i4 30V - 14ohm*i2 - 6ohm*i2 = 0 30 - 1.5*i4 - 6*i4 = 0 I solved them to come up with i4 = 4 A i1 = 5.5 A i2 = 1.5 A But all are wrong, I am sure I am missing something big especially since i3 and i5 are...

What is KCL? Edit: Wait I think you mean Kirchhoff's law lol my bad.

The point is to find currents i1,2,3,4, and 5 in the picture. R1 = 14 Ohms R2 = 6 Ohms This is my work so far. 5 Currents, 5 Loops, 5 Equations, that is the rule (or so I think) The way I am looking at it, there are 6 Loops, so if someone could reduce it to 5 that'd be of some help...

Yo-Yo's Inertia A yo-yo has a rotational inertia of 810 g · cm2 and a mass of 190 g. Its axle radius is 3.6 mm, and its string is 70 cm long. The yo-yo rolls from rest down to the end of the string. I've tried 4 or 5 ways to get linear accel, but none work. b, c, d, and e are straight...

An early method of measuring the speed of light makes use of a rotating slotted wheel. A beam of light passes through a slot at the outside edge of the wheel, travels to a distant mirror, and returns to the wheel just in time to pass through the next slot in the wheel. One such slotted wheel has...

I got it all, thanks though

one block has a mass M = 500 g, the other has mass m = 460 g, and the pulley, which is mounted in horizontal frictionless bearings, has a radius of 5.00 cm. When released from rest, the heavier block falls 85.5 cm in 2.47 s (without the cord slipping on the pulley). First I did conversions...

That doesn't tell me much, how do I find force in the direction of motion then with a surface that is sloping like that?

A perfect hemisphere of frictionless ice has radius R = 8 meters. Sitting on the top of the ice, motionless, is a box of mass m = 10 kg. The box starts to slide to the right, down the sloping surface of the ice. After it has moved by an angle 14 degrees from the top, how much work has...

Got it all even though no one helps, thanks anyway lol, someone delete this please?

I managed to get part 3 and 4, but the Part 2 with 12.375 J is still wrong, It looks perfect to me, did I miss something?

A block of mass 240 grams is dropped onto a relaxed vertical spring that has a spring constant 11 N/cm as shown on the figure. The block becomes attached to the spring and compresses the spring 15 cm before momentarily stopping. First Conversions: 240g = .24kg, 11 N/cm = 1100 N/m, 15cm =...

So the answer to the X component would be -1.7? or 6.25/28.56 * -1.7?

I am absolutely sure about Y = 0. Besides that, only things known are D and L

(Assume it is constant 1kg) (5.9m(1kg) ) / (1kg) = 5.9m <- from the Y axis, for center 5.9/2 = 2.95m This goes for top and bottom sections. (5.9m-2.5m)(1kg) / (1kg) <- 3.4m <- from the Y ais, for center 5.9/2 = 1.7m 1.7m(1kg) + 2.95m(1kg) + 2.95(1kg) / (3kg) = 2.53m Since the origin...