For this post, I'll be mainly referring to this photoelectric equation:
Fig 1: Photoelectric equation
1) Is 'e' the charge of an electron, ie. a negative value? Or just an elementary charge, ie. a positive value?
2) Is stopping potential (Vs) a positive or negative value? Because in my...
Homework Statement
A power station generates 100kW of power at a voltage of 10kV. Given that the connecting cables in the primary and secondary circuit each have a resistance of 10Ω, find the turn ratio required for an ideal step-down transformer to bring electrical energy to the home at 240V...
Homework Statement
The armature of a simple motor consists of a square coil and carries a current of 0.55 A just before it starts to move. The coil is positioned perpendicular to a magnetic field. Explain briefly why the current falls below 0.55A once the coil of the motor is rotating...
Oh okay. But if you refer to the diagram I drew on the left, I assumed that there's a 0.4m block of blade on the ground, such that the oscillation has an amplitude of only 0.7m. So 0.55m off the ground would mean 0.15m above the 'block'. So that means 0.15m above the minimum point of oscillation...
Oh, so just to clarify, for the ##x = -x₀cos(wt)## formula, if I substitute a value of ##x##, the ##t## that I find would refer to the time taken for the object to travel from the equilibrium point to the displaced point?
But even if the t1 refers to the time taken to travel from the...
Homework Statement
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Homework Equations
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x = x₀cos(wt) (or x = -x₀cos(wt) , depending on the graph shape)
x = x₀sin(wt)
ω = 2π / TThe Attempt at a Solution
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I am confused as I have never encountered any oscillatory object with a thickness. Because if I take the middle of...
Hi!
I have a few questions about resonance:
1) What exactly is the "amplitude of driver of oscillation"? And why is the amplitude of the driven object equal to the amplitude of the driver right from the start when the driver frequency is 0?
2) Is the driven system originally oscillating?
3)...