OK I understand what needs to be done and found the answer, so thank you so much. For posterity's sake however, I considered the term,
\frac{1}{(z-2\pi)\left[\frac{1}{2!}-\frac{(z-2\pi)^2}{4!}+\cdots\right]},
Found the closed-form of the series, found its reciprocal, and turned it back into a...