Recent content by booooo

simply using y(t) = X cos(2 π t / T) ? is that right

Do you mean by using this equation ?y(t) = X cos(2 π t / T + φ) btw what isφ

how do you know if the woman is above or below her rest position?

oh thanks! now i get the answer ;)

I've got the first question! yey can someone help me with the second... seriously got no idea on that one...

oh right! I've got the answer now ;) Thank you sooo much

no... I am getting 2.81*10^20 ... couldn't figure out where has gone wrong...

oh.. that was a typo.. should be 'increase their lung volume by 4.880 L' and so 0.00593 for V

oh! stupid me! so that will be 0.00513m3 ummmm in getting 2.44*10^23 ..

for the first question, I tried PV=nRT .. used the gauge pressure as P , T=288k, n=0.300998 (its the moles of gas in balloon)... i got the answer 2.72338*10-3 .. the correct answer should be 1.93*10-3 then the second question... i used m=Q/cdT .. I don't know which temp should I use for the...

the volume of lung? 1.7+4.58m3 then times 6.02*10e23...?

awwwww I just used PV=nRT P- atm= 202.658 V=5.13 T=309.19 but its still not right... where went wrong??

I used V1/T1=V2/T2 where V1=4.88, T1=309.19k, T2=286.7k and V2 is the unknown. then I put V2 in the formula PV2=nRT P-3.5atm T-309.19 I got 6.16^e-3 but the answer is 4.92e+23 ... far out

A submarine has run into trouble and is stuck at the bottom of the ocean. Several people are on board and must make their way to the surface without any diving gear. The air pressure aboard the submarine is 3.400 atm. The air temperature inside the submarine is 16.36 °C and you can take body...

-A spherical balloon is inflated to a diameter of 20.0 cm. Assume that the gas in the balloon is of atmospheric pressure (101.3 kPa) and is at a temperature of 20.0 °C. It is then taken by a diver 15.0 m under the sea. The temperature of the seawater at this depth is 16.0 °C . Density of...