Recent content by Breadsticks

Right, there would be length contraction but what about the distance the train has moved while the wave is moving?

Thanks for the reply. If the train was moving at a non-negligible fraction of the speed of light, I would then simply find where the waves meet to figure distance for each then use the above procedure with the modified distances?

Homework Statement 1-9: Assume the train is 1.0km long as measured by the observer at C' and is moving at 150km/h. What time interval between the arrival of the wave fronts at C' is measured by the observer at C in S? [/B]Homework EquationsThe Attempt at a Solution The solution from the...

Homework Statement If a pilot accelerates at more than 4g, he begins to “gray out” but doesn’t completely lose consciousness. (a) Assuming constant acceleration, what is the shortest time that a jet pilot starting from rest can take to reach Mach 4 (four times the speed of sound) without...

V0 is the initial velocity for the entire movement. Although the ball's velocity will be -96 when Δy=0, it's not the velocity that is needed for the equation. Just to be clear, it takes 6 seconds for the ball to reach max height and fall back down to the level it was thrown at. Then it takes...

Δy=V0t+1/2at2 Using displacement and not the total distance traveled, -80 feet= (96 feet/s)t+(1/2)(-32.17 feet/s2)t2 Solve for t, t= -0.74 s and t=6.7 s. A negative time isn't possible so t=6.7s is the right answer.

The shape of the ball's trajectory is a parabola. The ball initially moves upwards then it comes back down. When the ball has fallen back to the level that it was thrown at, Δy=0. If we put this into the equation, then you will get 6 seconds, like you calculated. However, the ball keeps moving...

I don't understand. Isn't the definition that rev=2π?

Homework Statement :[/B] Your car tire is rotating at 3.5 rev/s when suddenly you press down hard on the accelerator. After traveling 200 m, the tire’s rotation has increased to 6.0 rev/s. What was the tire’s angular acceleration? Give your answer in rad/s2. Homework Equations :[/B]...

Homework Statement A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 30 m/s^2 for 30s, then runs out of fuel. Ignore any air resistance effects. What is the rocket’s maximum altitude? Homework Equations Δx=V0t+(1/2)at2 V=V0+at 2aΔx=V2-V02...

Yes, thank you.

Okay, thank you. One more question, in this problem's case, the expression for the x-component would be magnitude*tan(theta), right?

I must've mistyped on my calculator because I did cos(47)/-cos(133) and got 2. Calculator memory is cleared so I'm not sure what I really typed in. So using the correct substitution, that the magnitudes are equal, I got the right answer. Thank you so much everyone, you've been really helpful...

Okay. Is there a way to make it work using x-component=magnitude*cos(theta) and y-component=magnitude*sin(theta) if I use two different angles (47 and 133)? I had A use an angle of 133 and B use 47. Then since they cancel each other out, I did magnitude(A)cos(theta)= -magnitude(B)cos(theta) and...

Ah, so I rotate the x,y axis by 90 degrees and I'm left with cos(theta). If I wanted to keep the x,y axis in the traditional location, is there an easy way to modify the equation?