Recent content by Brittykitty

Thank you so much :)

I just have a question that I'm hoping someone can help me with. I just finished a physics course where the final exam weighs at 40% of my final mark while the assignments weight at 60% which =100% total For my assignments I got a terrible 843.99 out of 1,408. I'm not quite sure what I got...

24m*15N=360?

So it would be -888J?

What formula would I use to find the work done to overcome friction? I sort of understand but am still a bit confused

A force of 52 N is applied to a 12 kg mass resting on a bench where the force of sliding friction is 15 N. The work done in overcoming friction while moving the object 24 m is w=fd w=(37N)(24m) w=888J Does this procedure seem correct ? :) Thank you!

Thank you so much! :) :) :)

2375 J =mgh (65)(9.81)=637.65 2375J/637.65 =3.72?

h=(2375J)(9.81) ?

m=65 g=(9.81) (h)=? J= 2375 I sort of it get it but still not sure.. terrible at physics

Thank you :) so since 2375 J =mg(h) do I need to rearrange it so its h= ?

How do I find delta h?

I'm not quite sure that I get it :( So when I find the force that will be my height? This is the most confusing question to me lol

A 65.0 kg student climbs a set of stairs in 25.0 s with a power output of 95 W. What is the vertical height of the stairs? I came up with the formula: W=P x (delta t) W=95w(25.0s) 2375 Im not sure how this comes into play: W = mg (delta h) Im really confused :|

30*-9.81?