Recent content by bushman91

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    Solve Math Word Problem: Bickford & Shawn Speed & Times

    thanks for the help, I should be able to get it now
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    Solve Math Word Problem: Bickford & Shawn Speed & Times

    Please explain how you set that up and the what the variables represent
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    Solve Math Word Problem: Bickford & Shawn Speed & Times

    Bickford traveled twice as fast as Shawn traveled. Thus, Bickford could travel the 320 miles to the reef in only 2 hours less than it took shawn to travel the 240-miles to Jane's house. Find the rates and times of both boys. Just having problems figuring out the formula and how to set it up...
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    Square Rooted varible by itself (/x)

    thanks guys, i was thinking that, but in the question it was dealing with string vibrations were 1050hz and 2700hz and 1mm.. original question: (1050)(/sqrt 1)=(2700)(/sqrt D) got to that last part and forgot what to do so i did it like this: if 1mm equals 1050hz - then 1/1050 would equal...
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    Square Rooted varible by itself (/x)

    Such a simple problem that I am stuck on... 1050=2700 /d 0.388=/d how do i get "d" by itself? ( the "/" is square root not divide) edit: is "D" diameter or distance... one is "d" and other is "D"
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