Recent content by BWE38

aha! I see what you are saying now. (llu+vll)^2 = uu + uv +vu + vv, which becomes llu+vll^2 = llull^2 + 2uv + llvll^2 llu+vll = llull +llvll, IFF 2uv = 0 Which in this case it isn't. Because uv is equal to 10.

Homework Statement If llull = 4, llvll = 5 and u dot v = 10, find llu+vll. u and v are vectors Homework Equations llu+vll = llull + llvll cauchy schwarz The Attempt at a Solution (1) llu+vll = llull + llvll (2) (llu+vll)^2 = (llull + llvll)^2 (3) (llu+vll)^2 = llull^2 +...

normal force=40.8cos13.5(9.81)=389.19N friction=μκ(Nf)=81.73 N x-direction= applied force - friction - weight= MA 294-81.73-40.8=40.8A 212.27 N - 40.8 kg= 40.8 kg A am I doing everything right so far?

I have my free body diagram attached.

A 40.8 kg box is being pulled up a 13.5 deg slope by a force of 294 N which is parallel to the slope. The coeffcient of kinetic friction between the box and the slope is 0.21. what is the acceleration of the box? ----------------------------------------------------- Equations: F=MA, Fk=μk(MA)...

vertical acceleration: 9.81 m/s^2 (change to negative value because if gravity and velocity are both positive the ball woudn't come back down), so therefore the gravity will be -9.81 m/s^2. horizontal velocity: is zero because air resistance is neglected and this means that it will travel at...

I tried to get vxi from the equation x=xo+voxT+1/2aT^2 then I substitued the value into the same equation and got 5.64 m= 5.64 m. I am really confused because I was expecting to get a time value. But I got the times canceling out and leaving me with meters=meters instead.

Kineamatic Equations V = Vo + at X - Xo = Vot + .5at2 v2 = vo2 + 2a(X - Xo) X - Xo = .5(Vo + V)t

I know that this is a two dimisional problem. But it seems like I don't have enough information to apply them to an equation of kineamatics. I need atleast three variables. I only have two x values that I can use: they are: x: 5.64 m A: 0 m/s^2 I only have (three y vaules) technically two...

Hi, I have a question that I can't finish, because it seems that I'm missing a particular variable. A little help would be very much appreciated. Question: An Olympic basketball player shoots towards a basket that is 5.64 m horizontally from her and 3.05 m above the floor. The ball leaves her...