Recent content by Calixto

Ok thanks HallsOfIvy, that helps a lot. And sorry tiny-tim for using such offensive language.

What the heck? The minimum monthly payment for a credit card is the larger of $5 or 1/25 of the outstanding balance. If the balance is less than $5, then the entire balance is due. If you make only the minimum payment each month, how long will it take to pay off a balance of $200? Clearly...

Describe a sequence of transformations that would transform the graph of y = 5cos3x into y = cos(3x + 6)

What would the domain of y = sqrt(cosx) be in mathematical terms. I know that it is all the reals that lie in the first and fourth quadrant of the unit circle, but how would you express that in mathematical terms?

Kudos to whoever can explain this! The original question was... how can I show that ... arctan(1/v) = (pi/2) - arctan(v) ? I understand how to do this the easy way... by forming a right triangle and so on and so forth... But could someone please explain to me what this is about? Mhill posted...

Thanks, I understand it now... But could you explain some more what you wrote about the logs and stuff? Just maybe explain where that comes from so I can impress my teacher :)

Ok, the other angle must be 180 - (90+ø), correct? And the tangent of this angle would be v... right? I'm still not seeing this proving business.

x = 3.2373049 The answer is quite simple to obtain. You had it right when you stated xˆ2 + 2x = ex + 3e. Now just set the equation = 0, so xˆ2 + (2-e)x - 3e = 0... At this point, it's only a matter of graphing it on your calculator or plugging it into the quad form. Either way, you will...

would you like an accurate approach to this problem, ArtofScience?

i knew this would confuse someone... that "n" you see is π, or pi... sorry. Does that help?

Here's how I think of it... I rearranged the equation so that arctan(1/v) + arctan(v) = π/2 And I understand how the tan of, say ø = 1/v, making the tan of, say ß = v. That part makes sense. The part I'm getting confused on is the π/2, and what that does to the equation.

I'm sorry, I don't understand what you did with the v. And what about the pi/2 part?

how can I show that ... arctan(1/v) = (π/2) - arctan(v) ?

I know I've been doing that, moving around variables and using the unit circle and right triangles, but I cannot seem to come across a substantial reason why they are equal. Any thoughts?

Daylight sinusoid any help appreciated :) A person finds that the number of hours of daylight at his home is approximately given by h = 12 + 4sin[2π/12(m-9)] where m represents the number of the month (January = 1, February = 2, etc.) a) At the person's location, how long...