Recent content by camron_m21

I think I figured it out; I reread the section in Jackson on Green's functions. I won't write out the full solution, but the general way to solve this is to use the Dirichlet formula, and to break up the surface integral into a sum over all the individual faces. Then realize that G(0,x') is the...

Homework Statement A closed volume is bounded by conducting surfaces that are the n sides of a regular polyhedron (n = 4,6,8,...). The n surfaces are at different potentials Vi, i = 1,2,3,...,n. Prove that the potential at the center of the polyhedron is the average of the potential on the n...

I'm looking for a good semiconductor optics textbook. I have Klingshirn's text, which has problems, but no solutions. As I'm using the textbook outside of university, I need solutions to problems, since I won't know if I'm right or wrong otherwise. I've also looked into Semiconductor Optics and...

I was getting confused on this one as well; it seemed too easy. My solution turned out to be: t = τγ, and x = Vτ/γ, by using dx/dt = γ dx/dτ. Hopefully this is correct, helpful, or both.

My problem is this: I have an algebraic expression, and I want to express it in terms of one variable divided by another. It's a fairly large expression, and I'd like to do it in mathematica before attempting it by hand. I've tried Simplify, FullSimplify and Solve, but none of these have done...

Yeah, sorry about that, that was just the formula for the general infinite square well. The formula I used replaces a with 2a, except in the t=0 function.

Scratch that, I figured it out. For anyone else stuck on this, calculate c_{n} the regular way, but use [0,a] for the integration bounds rather than [0,2a], since the initial function at t=0 is 0 for x > a.

Homework Statement Griffiths Intro to Quantum, problem 2.38: A particle of mass m is in the ground state of the infinite square well. Suddenly the well expands to twice its original size: the right wall moving from a to 2a, leaving the wave function (momentarily) undisturbed. The energy of...