I understand the problem is saying that the particle is starting a distance ds, but i still don't understand how that helps me solve the problem. Is ds somehow related to d cause I just don't see it.
Can you please elaborate on what you mean? I don't know if you are saying that is the speed at d or if you are asking where d is at.
I see it now the (2k)1/2 is actually a (8k)1/2
So since V = U/Q I can set it as (2kλπa)/(a2 + d2)1/2 = U/Q since the Q is the same as the one the ring has I can replace Q as λL since L = 2πa, Q = λ2πa So U = (4kπ2λ2a2)/(a2 + d2)1/2 and U = KE = 1/2mv2, so v2 = (2kπ2λ2a2)/(m(a2 + d2)1/2)
then I take the square of both sides and I get v =...
Homework Statement
A ring of radius a is made from a charge wire with a uniform charge density λ.
a) Calculate the electric potential due to the ring as a function of distance from its center along the axis of the ring passing through the center, perpendicular to its plane
b) If a particle...
We were going over linear independents in class and my professor said that if y1 and y2 are linearly independent then the ratio of y2/y1 is not a constant, but he never explained why it is not a constant.
Homework Statement
Gas particles of a particular gas have a speed distribution function of
fv = Cv/(v2 +vo2)2
a. Find the value of C
b. Calculate the most probable speed
c. What fractions of the particles are moving faster than the most probable speed
Homework EquationsThe Attempt at a...