Hello,
I'd like to calculate the max contact pressure in the below assembly, just before contact loss between the beam and the wall. The beam is clamped to the wall with a pretensioned screw, and sustaining a force at his gravity center.
I'm assuming all bodies dimensionnaly stable (no...
Hello,
Could somebody help me finding the relation between the horizontal force, the weight acting vertically, and the slopes Angle (same for both) that correspond to static equilibrium of the blue ball ?
In a first step, I'd like to study this problem without considering friction at all. And...
Hello Hesch !
Thanks to your help I did it this way :
E1 (just before hit) = m*g*(L-xp) + ½*m*v2 + ½*k*xp2
with v = √(2*g*h)
E2 (just before rebund phase) = m*g*(L -xp -xadd) + 0 + ½*k*(xp + xadd)2
Then E1 = E2 led me to this factorisation form (xadd as variable) :
½*k*xadd2 + (k*xp - m*g)*xadd...
Hello everybody,
I'm trying to figure out how to calculate xadd, the additional compression of a preloaded spring (initially compressed of xp) on which a mass is dropped from a height "h".
I also wonder :
- if the final compressed spring length is the same with or without preload ?
- if the...
Thanks a lot for this resolution method. I feel closer to the results now.
Indeed, I know the value of Fp and can adjust it. I can also change the mass of the ball (however in a quite small range, something like +/-10%). I have to go sleeping now but I'll work on it tomorrow and let you know how...
Hello Simon and thanks for your answer.
To make a first approximation I indeed consider that the horizontal speed is constant at all times. The translation motion is done by an electric motor, which one is switch-off when the ball pass over the cam (sensor), but due to the mechanical clearance...
Hello,
I'm now working on a charge limiting system. I tried modeling it an easy way to be studied.
https://imageshack.us/a/img842/4572/3zvv.png
A steel ball (mass "m") moves horizontaly at a continuous speed to the right.
The ball has to pass over the obstacle (king of cam) which...