Recent content by carbz

well, the C is always annoying, but thank you.

yes, you said that u = x+2 The derivative of that is du = 1dx That would only get: \int\frac{x}{u^{2}} Then you would solve x equal to u-2? That would get: \int\frac{u-2}{u^{2}} That would make: \int\frac{1}{u} - \int\frac{2}{u^{2}} = ln(x) - \frac{-2}{u} Then, of course, you...

What both of you are saying will produce: \int\frac{x}{u^{2}} Shouldn't the x in the numerator be apart of it too?

I did use that too for the first one, and I could not find an answer. When I did it, I got 2=0 which is not an answer. All right, thank you for the second one.

I actually have two here, so I will just list both: Homework Statement \int\frac{x}{x^{2}+4x+4}dx Homework Equations None The Attempt at a Solution I tried this one twice. I honestly have no idea how to do it, and I used integration by parts. The first time, I reduced it down...

Allright, thanks. I got both problems worked out correctly now.

I have two of these here... Homework Statement Find the derivative Homework Equations (t^2-\frac{4}{t^4})*t^3 The Attempt at a Solution This is how far I got: (t^2-4t(^-4))(t(^3)) (t^2-4t(^-4))(3t(^2))+(t^3)(2t+16t(^-5)) Homework Statement Find the derivative...

It is infinite on both sides of the point, it doesn't exist.

allright, thank you

allright, thankyou.

it's not from my book, it was my teacher.

it is 1, not 0.

[SOLVED] Just one more limit problem. Homework Statement Find the limit Homework Equations \lim_{x \rightarrow 0} (x^2 - \frac{1}{x}) The Attempt at a Solution I got does not exist for this limit. This is since, when you break it down to two parts, the 1/x is undefined at 0.

(x-3}^2. Oh yeah, so that takes away the square root, and after everything, it leaves 0. thank you.

Yes, I tried doing that. (x-3)(x-3) However, I forgot how to get rid of that radical. Squaring wouldn't work, so I have no idea. Also, no thoughts on the first one?