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I actually have two here, so I will just list both:

[tex]\int\frac{x}{x^{2}+4x+4}dx[/tex]

None

I tried this one twice. I honestly have no idea how to do it, and I used integration by parts. The first time, I reduced it down to:

[tex]\int\frac{1}{x} + \frac{1}{4} + \frac{x}{4}dx[/tex]

But, this is wrong.

I tried it a second time by using integration by parts to obtain:

[tex]\int\frac{x}{(x+2)(x+2)}dx[/tex], then I reduced that down, since integration by parts does not work. So, I was hoping to know what I am susposed to do.

The second one is a bit different:

[tex]/int[/tex] [tex](tan^{2}(x))dx[/tex]

[tex]tan^{2}(x) + 1 = sec^{2}[/tex]

I used the regular formula that I listed to get:

[tex]\int(sec^{2}(x) - 1)dx[/tex].

I just integrated to: [tex] tan^{2} - x + c [/tex]

I wanted to see if this one is correct.

Thankyou for your help.

## Homework Statement

[tex]\int\frac{x}{x^{2}+4x+4}dx[/tex]

## Homework Equations

None

## The Attempt at a Solution

I tried this one twice. I honestly have no idea how to do it, and I used integration by parts. The first time, I reduced it down to:

[tex]\int\frac{1}{x} + \frac{1}{4} + \frac{x}{4}dx[/tex]

But, this is wrong.

I tried it a second time by using integration by parts to obtain:

[tex]\int\frac{x}{(x+2)(x+2)}dx[/tex], then I reduced that down, since integration by parts does not work. So, I was hoping to know what I am susposed to do.

The second one is a bit different:

## Homework Statement

[tex]/int[/tex] [tex](tan^{2}(x))dx[/tex]

## Homework Equations

[tex]tan^{2}(x) + 1 = sec^{2}[/tex]

## The Attempt at a Solution

I used the regular formula that I listed to get:

[tex]\int(sec^{2}(x) - 1)dx[/tex].

I just integrated to: [tex] tan^{2} - x + c [/tex]

I wanted to see if this one is correct.

Thankyou for your help.

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