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I actually have two here, so I will just list both:
[tex]\int\frac{x}{x^{2}+4x+4}dx[/tex]
None
I tried this one twice. I honestly have no idea how to do it, and I used integration by parts. The first time, I reduced it down to:
[tex]\int\frac{1}{x} + \frac{1}{4} + \frac{x}{4}dx[/tex]
But, this is wrong.
I tried it a second time by using integration by parts to obtain:
[tex]\int\frac{x}{(x+2)(x+2)}dx[/tex], then I reduced that down, since integration by parts does not work. So, I was hoping to know what I am susposed to do.
The second one is a bit different:
[tex]/int[/tex] [tex](tan^{2}(x))dx[/tex]
[tex]tan^{2}(x) + 1 = sec^{2}[/tex]
I used the regular formula that I listed to get:
[tex]\int(sec^{2}(x) - 1)dx[/tex].
I just integrated to: [tex] tan^{2} - x + c [/tex]
I wanted to see if this one is correct.
Thankyou for your help.
Homework Statement
[tex]\int\frac{x}{x^{2}+4x+4}dx[/tex]
Homework Equations
None
The Attempt at a Solution
I tried this one twice. I honestly have no idea how to do it, and I used integration by parts. The first time, I reduced it down to:
[tex]\int\frac{1}{x} + \frac{1}{4} + \frac{x}{4}dx[/tex]
But, this is wrong.
I tried it a second time by using integration by parts to obtain:
[tex]\int\frac{x}{(x+2)(x+2)}dx[/tex], then I reduced that down, since integration by parts does not work. So, I was hoping to know what I am susposed to do.
The second one is a bit different:
Homework Statement
[tex]/int[/tex] [tex](tan^{2}(x))dx[/tex]
Homework Equations
[tex]tan^{2}(x) + 1 = sec^{2}[/tex]
The Attempt at a Solution
I used the regular formula that I listed to get:
[tex]\int(sec^{2}(x) - 1)dx[/tex].
I just integrated to: [tex] tan^{2} - x + c [/tex]
I wanted to see if this one is correct.
Thankyou for your help.
Last edited: