This precisely. If you put a Concave Lens in front of an image (make the converging rays that form the said image, fall on the concave lens before they can intersect and form he image) then that image should act as an object (virtual?) for the concave lens.
So basically an actual object that...
A concave lens always forms a virtual image (for a real object), will it always form a real image for a virtual object? (that is, when rays converge on it)
If yes, why?
If no, why?
I completely agree. But my point is that permittivity and permeability are experimentally derived.
Why not use 9 * 10^9 and 10^(-7) directly. As I proved earlier they do not deform the equation in any major way.
You can use K here too. epsilon(naught)/epsilon = K/K(naught)
No it doesn't really hide it.
k = 1/[4(pi)(epislon)]
Let l = mu/4(Pi) (I know l doesn't exist but bear with me.)
(I really need to learn how to type those formulae.)
then
epsilon = 1/[4(pi)(k)]
mu = 4(Pi)l...
That is the reason I thought of seconds after I clicked the Submit button, it does seem a likely reason but I will wait and see if someone knows something better.
Why use k = 1/[4(pi)(epislon)] and epsilon = 8.8 * 10^(-12) and subsequently, k = 9 * 10^9
It could simply be k = 9 * 10^9, and different k for different medium instead of different permittivity for different medium.
What I mean is why does Pi, (I can handle the 4) comes into the...
Okay, so I went through all. I somewhat understood what DH said (I am going to have to look at it all more closely), what sachav said went over my head abut I think phyzguy got what I was looking for.
I have to leave for class soon but thank you so much for your replies. Basically, I wanted confirmation that there is some significance with 2.71... and there is, I am going to read all the posts when i get back.
Ok, so this has been bothering me for a while.
Integral of (1/x)dx = log of x to the base e.
My question is, why e? Why can't it be instead to a base 3.14? Or any other number.
I am guessing there is some reason. 2.71 was not chosen at random.
I have searched a lot but can not seem...
Sorry about that, it should be
a = g((R-2x)/R) where g = 9.8, r = radius of earth, x = the depth to which the body is inside the earth.
I am not used to writing formulae like this so...>_<
Yes, I do.
On another note: No edit button?
A few months ago I was surfing idly and found this little thing called a Gravity Train. For those who do not know what it is, see http://en.wikipedia.org/wiki/Gravity_railroad" .
After reading about it I thought maybe I should try and find out how much time it would take (42.2 minutes) but...