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A concave lens always forms a virtual image (for a real object), will it always form a real image for a virtual object? (that is, when rays converge on it)
If yes, why?
If no, why?
If yes, why?
If no, why?
They Diverge?Ask yourself what happens to the rays leaving an object when they pass through a concave lens.
Yes?Would they ever be brought together to form a real image?
There's your answer.
btw, what is a "virtual object"? (I missed that when I first read it).
This precisely. If you put a Concave Lens in front of an image (make the converging rays that form the said image, fall on the concave lens before they can intersect and form he image) then that image should act as an object (virtual?) for the concave lens.if you have a convex lens, producing a real image and you put a concave lens between the first lens and the image it forms,.
the original (real) image as you put it is no longer real because it was never formed, right? The rays were supposed to intersect but the lens intercepted them before that could happen. That is what I mean by a virtual object.then the resulting (real) image will be formed a bit further away than the original (real) image
Are you familiar with the thin-lens equation? If so, you can answer this question for yourself.So again, for a virtual object, will a concave lens Always form real image?