Concave Lens _ Image Formation

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Discussion Overview

The discussion revolves around the image formation properties of concave lenses, particularly in relation to virtual objects. Participants explore whether a concave lens can always produce a real image when a virtual object is placed in front of it, and they examine the implications of ray divergence and lens combinations.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • Some participants assert that a concave lens always forms a virtual image for a real object and question whether it can form a real image for a virtual object.
  • Others argue that rays diverging from a virtual object would not converge to form a real image, suggesting that they would continue to spread apart.
  • A participant introduces the concept of using a convex lens to create a real image, which is then affected by a concave lens placed in between, potentially altering the image's position.
  • There is a discussion about the definition of a "virtual object," with some participants clarifying that it refers to an image that acts as an object for the lens.
  • One participant mentions that the outcome of image formation depends on the focal lengths of the lenses involved and their relative positions, indicating that no general rule applies.
  • Another participant references the thin-lens equation as a means to analyze the situation, implying that understanding this equation could help answer the original question.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether a concave lens will always form a real image for a virtual object. Multiple competing views are presented regarding the behavior of light rays and the definitions of virtual objects.

Contextual Notes

There are unresolved aspects regarding the definitions of virtual objects and intermediate images, as well as the specific conditions under which different lenses interact. The discussion also highlights the dependence on the focal lengths and positions of the lenses involved.

Who May Find This Useful

This discussion may be of interest to students and enthusiasts of optics, particularly those exploring lens behavior and image formation principles in physics.

-Castiel-
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A concave lens always forms a virtual image (for a real object), will it always form a real image for a virtual object? (that is, when rays converge on it)

If yes, why?

If no, why?
 
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Ask yourself what happens to the rays leaving an object when they pass through a concave lens. Would they ever be brought together to form a real image?
There's your answer.
 
sophiecentaur said:
Ask yourself what happens to the rays leaving an object when they pass through a concave lens.

They Diverge?

sophiecentaur said:
Would they ever be brought together to form a real image?
There's your answer.

Yes?
 
If two rays are, as you say, 'diverging' then how can they meet at a point to form a real image? They are surely getting further and further apart. No?

btw, what is a "virtual object"? (I missed that when I first read it).
 
However . . . . if you have a convex lens, producing a real image and you put a concave lens between the first lens and the image it forms, then the resulting (real) image will be formed a bit further away than the original (real) image.
 
sophiecentaur said:
btw, what is a "virtual object"? (I missed that when I first read it).

sophiecentaur said:
if you have a convex lens, producing a real image and you put a concave lens between the first lens and the image it forms,.

This precisely. If you put a Concave Lens in front of an image (make the converging rays that form the said image, fall on the concave lens before they can intersect and form he image) then that image should act as an object (virtual?) for the concave lens.

So basically an actual object that you place in front of a lens, is a real object.

sophiecentaur said:
then the resulting (real) image will be formed a bit further away than the original (real) image

the original (real) image as you put it is no longer real because it was never formed, right? The rays were supposed to intersect but the lens intercepted them before that could happen. That is what I mean by a virtual object.

So again, for a virtual object, will a concave lens Always form real image?

That is if two converging rays were to fall on a concave lens could it diverge them so much that they appear to come from behind the mirror as opposed to only shifting a bit further.
 
You are talking of an intermediate image and not a virtual object here, I think.

In answer to your original question, I would say that you can produce a real or virtual image, depending on the focal lengths of the two lenses and the position.
A Galilean telescope has a convex lens with a concave eyepiece lens - producing a virtual image at a distance which you can actually focus you eye on. The optics inside some camera lenses produces a shifted real image because of the presence of a concave element. So there is no general rule.
 
-Castiel- said:
So again, for a virtual object, will a concave lens Always form real image?

Are you familiar with the thin-lens equation? If so, you can answer this question for yourself.
 

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