Recent content by catherines

Silly textbook... Thanks!

Homework Statement The motion depicted in Figure 1 shows the path of a team in a car rally held in a rural area where the speed limit is 80 km/h. In the car rally, points are deducted for anyone determined to be breaking the speed limit. c) Determine the average velocity (magnitude and...

Because L2-L1 = 1/2 lambda because the difference between any 2 resonant lengths in a closed tube is 1/2lambda. So knowing that: 1/2lambda = L2-L1 lambda = 2(L2-L1)

oh. yeah. warmfire540's answer looks right. gee...this is a good sign... i have a physics exam on monday and i can't get these questions right!

Errr, I think the question is wrong or something, because the resonant lengths are supposed to be 1/4 lambda (lambda is wavelength), 3/4 lambda, 5/4 lambda, etc... So I think either your L1 or L2 is incorrectly given. But otherwise, I think the formula you're using should be fine...I don't...

Are both velocities for t=7.0s?

Superwoman was seen packing up a suspicious bundle into a wagon, which has a total mass of 25.0 kg and is at rest. She pulls the wagon towards the east with an applied force of 60.0 N, which makes an angle of 35.0° above the horizontal. The coefficient of friction is 0.100 between the wagon...

Oh! I got it! It turns out, the units of work for that equation wasn't given, so I just assumed it was Joules. But it was acutally kJ. And it turns out, for distance you had to use feet and I was using metres, so I got it all figured out now. Thank you so much for your help!

I'm doing a science fair project about swimming. Is it crazy for a swimmer (just pulling, no kicking) swimming a length of freestyle pull only to take 400-700 J of work? I'm using an equation W = kv^2s where k is a constant, v is velocity, and s is the distance. The k that is provided with...