Recent content by Cheezay

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    Relativistic momentum football problem

    p= 82.1*2/[sqrt(1-2^2/3^2)] p= 220.297 220.297=126*v/[sqrt(1-(v^2/3^2)] v= 1.94m/s which is not correct
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    Relativistic momentum football problem

    Homework Statement A football player with a mass of 82.1 kg and a speed of 2.00 m/s collides head-on with a player from the opposing team whose mass is 126 kg. The players stick together and are at rest after the collision. Calculate the speed of the second player, assuming the speed of...
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    Relativistic Addition of Electron Velocities

    Ok.. I've figured it out. Thanks for the help!
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    Length Contraction and a Relativistic Angle

    I see. Lo will be the distance from the wall to the base of the ladder.
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    Relativistic Addition of Electron Velocities

    Ok. So considering that a = electron 1, b = electron 2, and c = lab... I now have Va/c= .822c, and because Va/b=-Vb/a.. i use -.424c for the speed of electron 2 relative to the lab. Now i solve for Vb/c. I'm fairly confident i have my equation set up correctly now, which means I'm making an...
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    Relativistic Addition of Electron Velocities

    Homework Statement An electron moves to the right in a laboratory accelerator with a speed of 0.822c. A second electron in a different accelerator moves to the left with a speed of 0.424c relative to the first electron. Calculate the speed of the second electron (in c) relative to the lab. Do...
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    Length Contraction and a Relativistic Angle

    Homework Statement A ladder 4.92 m long leans against a wall inside a spaceship. From the point of view of a person on the ship, the base of the ladder is 3.13 m from the wall, and the top of the ladder is 4.00 m above the floor. The spaceship moves past the Earth with a speed of 0.919c in a...
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    Determing the new Near Point after correcting myopia with glasses

    Homework Statement 1.Without glasses, your uncle Albert can see things clearly only if they are between 28.4 cm and 137 cm from his eyes. What power eyeglass lens will correct your uncle's myopia? Assume the lenses will sit 2.47 cm from his eyes. Give answer in diopters. Do not enter unit...
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    Max distance of resolution from 2 point sources of light

    Homework Statement Two point sources of light are separated by 4.91 cm. As viewed through a 12.1 μm diameter pinhole, what is the maximum distance from which they can be resolved if red light (λ = 690 nm) is used? Homework Equations sinθ = 1.22*(λ/D) y= L*tan θ The Attempt at a...
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    Image Distance of a concave mirror ( with algebra)

    Thanks v_bachtiar, that helped a lot!
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    Image Distance of a concave mirror ( with algebra)

    Yes, that's how it works out. But solving for do, i get a wrong answer. Perhaps i have my equation set up wrong?
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    Image Distance of a concave mirror ( with algebra)

    Homework Statement A concave mirror with a focal length of 34.4 cm produces an image whose distance from the mirror is one-third the object distance. Calculate the object distance. Homework Equations (1/f)=(1/do) + (1/di) The Attempt at a Solution I know that i have to use the...
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    Unpolrized light passes through 2 polarizers

    Then I/Io= .5 x cos^2(theta). Thanks so much for the help!
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    Unpolrized light passes through 2 polarizers

    No, I'm sorry i don't see how to solve for that. I thought maybe it might be 1/2 the incident intensity, but that answer is not correct.
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    Unpolrized light passes through 2 polarizers

    Homework Statement Unpolarized light passes through two polarizers whose transmission axes are at an angle of 28.1° with respect to each other. What fraction of the incident intensity is transmitted through the polarizers? Homework Equations I=.5xIoxcos^2(theta) The Attempt at a...
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