Recent content by Coastal

This is a very simple molar mass problem. First, convert kg to g. Then, multiply the number of grams by the mol/molar mass ratio. Use the molar mass of H2O. Since grams will be being multiplied by #mols/grams, the grams cancel, leaving the number of mols in 1 kg of water/ice.

Homework Statement For the system 2 CO2 = 2 CO + O2, ∆H= 510 kJ the percentage decomposition of CO2 changes w/ temperature as follows. Temp, K...% Decomposition 1500...0.048 2500...17.6 3000...54.8 Calculate the equilibrium constants, plot lnK vs. 1/T. In the graph, find the slope and...

Alright, I think I got an answer. tanTheta = V²/rg = Us*m*g Theta = Tan -1 (V²/rg) = 26.6 degrees. Since mass isn't really a factor, I tested the answer with the equation tanTheta = Us*m*g. Us = tanTheta / m*g. tan26.6 / 800kg(arbitrary)*9.81m/s² = Us = .00006 which is basically...

Maybe it's the way I'm looking at it, but if there's no friction, the car would slide immediately. So isn't it impossible to take a curve without friction, even if it is banked at an angle? Is this a trick question :confused:

The common variables are the Normal force and the mass, neither of which would effect the angle. The thing I could think of would be combining the equations, since sin divided by cos equals tangent. The normal forces would cancel out resulting in the equation tanTheta = v² / rg But where does...

Homework Statement Part 1: Rounding a flat, unbanked curve, which has a radius (r), the coefficient of static friction between the car and the road is 0.5. Find the max speed you can take the curve without sliding. Radius (r) = 25 m I'll be using (Us) to denote the coefficient of static...

Entered 1.06 as my answer and got it wrong. Can someone at least explain it to me so I am able to do a problem like this come time for an exam?

Ok, so with the height being 12m... I got t=1.12s. So would the correct answer would be x=(1.34cos45)*1.12 = 1.06?

Hmm, I'm still getting the wrong answer. The initial height would be 10.75m (I think). Radius + 1/2 Radius + 1.75m = 10.75. The initial Y velocity = .947 m/s. This is where I might be going wrong... I added gravity to the initial Y... so .947 + 9.81 = 10.75 m... so I am getting t=1 second. Then...

Maybe I'm not thinking about it right. I used the 3rd formula to try and get t, but to get the left side of the equation (Vy), I did 1.34sin45, which is the same as the first part of the right side of the equation, meaning (gt) would be equal to zero... which can't be right. Then tried 1.34 =...

Homework Statement Fairgoers ride a Ferris wheel with a radius of 6.00 m, the bottom of which is 1.75 m from the ground. The wheel completes one revolution every 28.0 s. A passenger drops his keys when he is three quarters of the way up and at an angle of 45° to the vertical. Where do the keys...

Yep, that worked fine. Thanks for your help!

The problem I am working on corresponds with a problem in a book I have that also has an answer. I used to formula V= Square root of 2*g*x (formula of velocity as a function of position). This V was listed as the answer for the final velocity in the book. Instead, I manipulated the velocity as a...

Homework Statement An astronaut on Jupiter drops a rock straight downward from a height of 1.05 m. If the acceleration of gravity on Jupiter is 24.8 m/s2, what is the speed of the rock just before it lands? Homework Equations g=24.8m/s2 speed=distance/timeThe Attempt at a Solution At first i...