Recent content by confused88

thanks!

Can someone please correct my working out... \frac{\beta^2}{(x-1)(x-2)} - \frac{\beta^2}{(x-1)^2} \frac{\beta^2(x-1)^2 - \beta^2(x-1)(x-2)}{(x-1)(x-2)(x-1)^2} \frac{\beta^2x^2 - \beta^2 -\beta^2(x^2 - 3x +2)}{(x-1)(x-2)(x-1)^2} \frac{3\beta^2 + 3\beta^2x}{(x-1)(x-2)(x-1)^2}...

Hi! Can someone help me prove that the variance for the inverse gamma is: \frac{\beta^2}{(\alpha - 1)^2 (\alpha -2)} I started with: E(x) = \int_0^\infty x \frac{\beta^{\alpha}}{\gamma(\alpha)}(\frac{1}{x})^{\alpha + 1} exp (\frac{-\beta}{x}) dx then i let y = \frac{\beta}{x}; dy =...

haha i think that you underestimate how dumb i am. But that's cool, thanks for the help but

sorry I am so dumb, coz i forgot all maths over the holidays.. but if y = x/z then how do you calculate dx/dy?

I'm just having trouble with the integration ><. Oh wells

Hi! I'm having trouble understanding my textbook, so can someone please explain to me how they got from \int1/(1+x)2 dx, with the range of the integral from 0 to x/n to 1 - n/(x+n) THank you So MuCh

ohhh wow thanks a lot!

Homework Statement Can someone please help me with integration of x(e^(-x-theta)) Thank you. My working is shown below The Attempt at a Solution u = x, du = 1 dx, dv = e^(-x-theta)) v = e^-x+theta+1 / theta + 1 the rest can be seen in the attachment. Can you please check it out, it...

Oh wow i get it now. Thank you!

Umm the first latex image generation is supposed to be an integral, The second is supposed to be a fraction, so e^integral of P(x) divided by (y1)^2 And the third one is another integral. Sorry I don't know what happened.. please help me

Umm the first latex image generation is supposed to be an integral, The second is supposed to be a fraction, so e^integral of P(x) divided by (y1)^2 And the third one is another integral. Sorry I don't know what happened.. please help me

Umm the first latex image generation is supposed to be an integral, The second is supposed to be a fraction, so e^integral of P(x) divided by (y1)^2 And the third one is another integral. Sorry I don't know what happened.. please help

Homework Statement Please help me with this, I would really appreciate it: Using the fact that y1 = x-1/2 cos x is a solution of the associated homogeneous problem, obtain the general solution of x2 y'' + x y' + (x2 - 1/4)y = x3/2 The Attempt at a Solution Well the first thing i...

Can someone please help me with very simple math.. and explain slowly how they got from 3(n+r)(n+r-1) + (n+r) to (n+r)(3n+3r-2)? I forgot how to factorise, so can someone help me do this please?