confused88 Messages 22 Reaction score 0 Thread starter Aug 12, 2009 #1 sorry I am so dumb, coz i forgot all maths over the holidays.. but if y = x/z then how do you calculate dx/dy?
sorry I am so dumb, coz i forgot all maths over the holidays.. but if y = x/z then how do you calculate dx/dy?
jgens Gold Member Messages 1,575 Reaction score 50 Aug 12, 2009 #2 Well, if [itex]y = x/z[/itex] then [itex]z*y = x[/itex]. Does that help? If [itex]z[/itex] is a variable and not a constant, then you'll need to use partial derivatives.
Well, if [itex]y = x/z[/itex] then [itex]z*y = x[/itex]. Does that help? If [itex]z[/itex] is a variable and not a constant, then you'll need to use partial derivatives.
confused88 Messages 22 Reaction score 0 Aug 12, 2009 #3 haha i think that you underestimate how dumb i am. But that's cool, thanks for the help but
jgens Gold Member Messages 1,575 Reaction score 50 Aug 12, 2009 #4 Well, if [itex]z[/itex] is a constant, then this derivative is a simple application of the power rule: [tex]\frac{d}{dy}(zy) = z = \frac{dx}{dy}[/tex] If [itex]z[/itex] is not a constant but a function rather, then we use partial derivatives so that we have: [tex]\frac{\partial}{\partial y}(zy) = z = \frac{\partial x}{\partial y}[/tex] It's also easy to derive these results using the definition of a derivative . . .
Well, if [itex]z[/itex] is a constant, then this derivative is a simple application of the power rule: [tex]\frac{d}{dy}(zy) = z = \frac{dx}{dy}[/tex] If [itex]z[/itex] is not a constant but a function rather, then we use partial derivatives so that we have: [tex]\frac{\partial}{\partial y}(zy) = z = \frac{\partial x}{\partial y}[/tex] It's also easy to derive these results using the definition of a derivative . . .