If y = x/z then how do you calculate dx/dy?

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Discussion Overview

The discussion revolves around the calculation of the derivative dx/dy given the equation y = x/z. Participants explore different scenarios regarding the nature of the variable z, considering both constant and variable cases, and the implications for differentiation.

Discussion Character

  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses uncertainty about their mathematical skills and seeks help with the derivative calculation.
  • Another participant suggests rewriting the equation as z*y = x and indicates that if z is a variable, partial derivatives should be used.
  • A further reply clarifies that if z is constant, the derivative can be computed using the power rule, leading to dx/dy = z.
  • If z is a function, the same approach applies but involves partial derivatives, resulting in ∂x/∂y = z.
  • There is a mention of deriving results using the definition of a derivative, though specifics are not provided.

Areas of Agreement / Disagreement

Participants present different views on whether z is a constant or a variable, leading to different approaches for calculating the derivative. The discussion remains unresolved regarding the specific context of z.

Contextual Notes

The discussion does not clarify the assumptions regarding the nature of z, nor does it resolve the implications of treating z as a constant versus a variable.

confused88
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sorry I am so dumb, coz i forgot all maths over the holidays..

but if y = x/z
then how do you calculate dx/dy?
 
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Well, if y = x/z then z*y = x. Does that help? If z is a variable and not a constant, then you'll need to use partial derivatives.
 


haha i think that you underestimate how dumb i am. But that's cool, thanks for the help but
 


Well, if z is a constant, then this derivative is a simple application of the power rule:

\frac{d}{dy}(zy) = z = \frac{dx}{dy}

If z is not a constant but a function rather, then we use partial derivatives so that we have:

\frac{\partial}{\partial y}(zy) = z = \frac{\partial x}{\partial y}

It's also easy to derive these results using the definition of a derivative . . .
 

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