Because MATLAB isn't required for chemical engineering majors at my school, but dynamics is, and this is a dynamics problem. I also didn't say I have no experience at all, but next to none, meaning very little. I can do basic computations but this one is out of my league.
I have next to no experience with matlab. I would try and solve for the initial velocity that I need for each given distance, but I'm not sure how to make that into a MATLAB code. Getting that by trial and error by hand would take an eternity.
Homework Statement
I have to write a MATLAB script that calculates the horizontal distance of a projectile fired from a cannon set at 45 degrees by a compressed spring. I know that the spring constant is 6 lb/in, the unstretched length of the spring is 1 foot, the mass of the projectile is 0.1...
OK, so setting u=2e2x, I get du=4e2x dx, and dx=1/4e2x du. Substituting that in, I get...
I=2π∫(e2x)(1/4)(1/e2x)√(1+u2) and then when I simplify...
I=1/2π∫√(1+u2) using a trig sub,
I=1/2π∫sec3θ dθ
Is this correct?
The problem is, find the surface area of the volume of revolution generated by rotating the curve y=e2x between x=0 and x=2 about the x-axis.
Here's what I have so far...
SA=∫y√(1+y2)dx
=∫e2x√(1+4e4x)dx
and from here I'm not really sure what to do. Any help would be appreciated.
Homework Statement
A lighthouse that rises 49 ft above the surface of the water sits on a rocky cliff that extends 19 feet from its base. A sailor on the deck of a ship sights the top of the lighthouse at an angle of 30 degrees above the horizontal. If the sailor's eye level is 14 ft above...
Homework Statement
An 18 meter ladder is sliding down a vertical wall at a rate of 2.5 m/s. Find the speed of the lower end of the ladder when it is 12 meters from the wall.
Homework Equations
Pythagorean Theorem
The Attempt at a Solution
Let h = height of the wall
L = length of the...
Homework Statement
Limit as h approaches 0 for [rad(5+h)-rad(5-h)]/h
Homework Equations
The Attempt at a Solution
limit as h approaches 0 for [(5+h)-(5-h)]/h[rad(5+h)+rad(5-h)]
limit as h approaches 0 for 2h/h[rad(5+h)+rad(5-h)]
limit as h approaches 0 for h/[rad(5+h)+rad(5-h)]
This...