1. The problem statement, all variables and given/known data A lighthouse that rises 49 ft above the surface of the water sits on a rocky cliff that extends 19 feet from its base. A sailor on the deck of a ship sights the top of the lighthouse at an angle of 30 degrees above the horizontal. If the sailor's eye level is 14 ft above the surface of the water, how far is the ship from the rocks? 2. Relevant equations tanx=opp/adj 3. The attempt at a solution tan30=35/x xtan30=35 x=35/(tan30) x=60.6 ft Since the lighthouse is 49 feet above the surface and the sailor is 14 feet above the surface, the opposite side of the triangle is 35 feet, but I can't get the right answer doing this.