So, if my position in the x direction is a function of time, like x=2t^2 the derivative of that is 4t which should be my velocity in the x direction. Then a second derivative should give me 4 and that should be my acceleration in the x direction. Am I on the right track?
For the formulas I have you still need \Delta x and \Delta t
v_x = lim_{\Delta t \rightarrow 0}\frac{\Delta x}{\Delta t}
...and yes, this is calculus based.
I feel like I've missed a lesson or missed something in class.
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Homework Statement
We've got an...
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I'm trying to find where this function increases and decreases:
f(x) = = - x^2 - 6x - 8
I can get the vertex (h, k), which works out [by my math] to be (3, -17).
I'm just not sure where to go from here to get information like:
point of increase and decrease
domain and range...