Recent content by cronusmin

so if the contact surface area(wheel) of both cars are same, what should the result be?

in case the Q is asking for the work done by the man, so any relation for the man pushing on the stair?

besides tat, the lecturer for the thermodynamics course is a professor in that subject... any idea for that?

the question is correct, i copy this from a thermodynamics course student. when i get the answer is 0J, i also felt surprised. how should it b 0J i think. is that the frame of reference the thermodynamics course consider is not same as physics course?

Q: a man(40kg) walks up the stair of 3m high, how much work done by the man? wat i think is, the man experienced the gravitational pull, so the man should get a work done of mgh=40*9.81*3 J, is this correct? but the answer from the thermodynamic course tutorial Q is 0 J. why? 2nd Q: a...

a car(54g)(toy) releases from a high place through a railway to a flat low place. by observation from an experiment, for sure there's some energy lost causing by the friction n drag force. 2nd time i do it, i add some mass(50g) for the car n releases again. i found tat the 2nd car's energy will...

haha...i thought that your hints maybe something like slowly pump in or faster pump in. thx

seem like its a big argue here... 1st at all, i do this experiment by using a closed container with air inside at the begining.then i use a machine to pump in the air. for sure tat the pressure inside will increase, i found tat the temperature also increase too. this is wat I've done b4. i...

wow, answering so fast...thank you guys let me try to think about it 1st

an experiment^^ in a closed container, means tat it has a constant volume. when i increase the air pressure inside(without heating), the result is the temperature will increase. why? can i have a theoretical explanation? thx for reading