Man Walks Up Stairs: Work Done?

  • Thread starter Thread starter cronusmin
  • Start date Start date
  • Tags Tags
    Work Work done
AI Thread Summary
The discussion centers on the calculation of work done by a man walking up and down stairs. The initial calculation suggests that work done is mgh (40kg * 9.81m/s² * 3m), but the thermodynamics course states the work done is 0 J. The reasoning behind this is that while the man exerts force, the stairs do not move, resulting in no work done on an external object. A second question about walking up and down concludes that the total work done is also 0 J due to zero net displacement. The conversation highlights a potential discrepancy between physics and thermodynamics interpretations of work.
cronusmin
Messages
10
Reaction score
0
Q: a man(40kg) walks up the stair of 3m high, how much work done by the man?

wat i think is, the man experienced the gravitational pull, so the man should get a work done of mgh=40*9.81*3 J, is this correct?

but the answer from the thermodynamic course tutorial Q is 0 J. why?

2nd Q: a man(40kg) walks up the stair of 3m high n walk down to floor again, how much work done by the man?

for this Q, i will answer 0 J, because the displacement is 0m.
 
Physics news on Phys.org
I disagree with the answer for question 1. Is that the exact question, word for word?
 
Snazzy said:
I disagree with the answer for question 1. Is that the exact question, word for word?

the question is correct, i copy this from a thermodynamics course student. when i get the answer is 0J, i also felt surprised. how should it b 0J i think. is that the frame of reference the thermodynamics course consider is not same as physics course?
 
Snazzy said:
I disagree with the answer for question 1. Is that the exact question, word for word?

besides tat, the lecturer for the thermodynamics course is a professor in that subject...
any idea for that?
 
Only work done on something else counts. The man has pushed against the stairs, but those haven't moved, so he has added no energy to anything else.
 
kamerling said:
Only work done on something else counts. The man has pushed against the stairs, but those haven't moved, so he has added no energy to anything else.

in case the Q is asking for the work done by the man, so any relation for the man pushing on the stair?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top