Can't see the image clearly but I think this is what I would do.
For the multiplication portion
[5^(6/24)][(5^(24/5))/(5^5)]
= [5^(6/24)][(5^(24/5))(5^-5)]
Hint: (x^2)*(x^3) =?
vs (x^2)^3?
I can't see the url outside of me replying. Anyways what about dividing the original equation by (x^2 + 1) and then attempting to factor whatever it is?
My bad, fixed the problem.My equation was wrong.
So from the previous equation
(x+1)=(x^2+1)(x-1)
I just factored out right hand side and minused (x+1) from both sides to get x^3 - x^2 + x - 1-(x+1)=0.
Supposed to have been
x^3-x^2-2=0
Don't know how to factor this one out.
Side Note: How did...
For x^4+... I just try to convert it to (x^2+...)(x^2+...) format by guessing tbh. I know how to factor cubes, the quadratic formula, and how to divide one polynomial by another.
Question 1:
(a) Show that the complex number i is a root of the equation
x^4 - 5x^3 + 7x^2 - 5x + 6 = 0
(b) Find the other roots of this equation
Work:
Well, I thought about factoring the equation into (x^2 + ...) (x^2+...) but I couldn't do it. Is there a method for that? Anyways the reason I...
First Question:
Solve the following system of equations
log{x+1}y=2
log{y+1}x=1/4
Work:
Turned them into equations
(x+1)^2=y (y+1)^(1/4)=x
Substituted second equation into the first equation
((y+1)^(1/4)+1)^2=y
factored out and eventually got
((y+1)^1/4)^2+2((y+1)^1/4)+1=y
Tried...