I got a problem with my notes in introduction to mechanics.
In the 1st picture, why the deceleration should be " a=-g-kv" instead of " a=-g+kv" ?
The air drag should be against the motion. the motion is downward, then the drag should be pointing upward. So I think it should be "positive"...
Diode is a PN junction
BJT is a PNP or NPN type junctions
Their working principle is similar. They are based on the different concentration of charge carriers (doping).
v_y ^2= u_y ^2+ 2a_ys
Let the upward direction as positive
For the y-components and
\theta
0 = u^2{ \sin^2{\theta}} -2gh
h = \frac {u^2 {\sin^2{\theta}}}{2g}
For the \frac {\theta}{2}
h = \frac {u^2 {\sin^2{\frac {\theta}{2}}}}{2g}
Due to the series configuration, Ic and Id are equal in magnitude but opposite in direction.
if Ia = 3A, Ic = 1A, then Id = -1A
Ia + Ic - Id - Ib = 0
3A + 1A - 1A - Ib = 0
as a result, Ia=Ib = 3A
1) There are some standard formats/ combinations of functions.
2) Sorry, I am not very clear about this question.
3) Question: I = \int_{0}^{\Pi} \frac{1}{{(a+b \cosx)^2}} dx
Answer : I = \frac {ab^2 \Pi}{(\sqrt{a^2-b^2})^3}
Yes. That's it.
f(2+h) = 2+h / 3+h
You should notice that h is not equal to -3 or x is not equal to -1 as x = 2+h . something over zero is meaningless.