Recent content by Dekoy

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    Magnetic Field, Proton, Dynamics

    Homework Statement A proton of charge +e and mass mp enters a uniform magnetic field B =B\hat{i}with an initial velocity Vi = vix\hat{i}+ viy\hat{j}. Without assuming any circular motion, show that its veloc- ity v at any later time t is given by v(t) = vix\hat{i}+ viy cos(eBt/mp)\hat{j}-viy...
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    Balistic Pendulum Velocity Approximation Formula Explanation and Solution

    I tried it using angular frequency since frequency is 1/time and x/time = velocity. It seems to work but I don't know if that's the right approach. Does anyone know if that's correct or if that's possible.
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    Calculating the Fourth Mass: A Rope and Four Masses

    I tried copying and pasting from a pdf file but it didn't work but it's really easy actually I already figured it out, :). Thanks anyways.
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    Calculating the Fourth Mass: A Rope and Four Masses

    Homework Statement 2. There are four masses hanging by a rope from the ceiling, as shown in the figure. Two of the tensions and three of the masses have been measured. Show that the fourth mass can be expressed as m4 =[m1T2/(T1 − T2)]− m2 − m3. Homework Equations F=ma, F1=-F2, T=ma...
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    What is the Maximum Horizontal Distance for a Gazilcher Launch?

    Here's the way I did it 1. We know that 45 degrees gives max height and max range. 2. Using projectile motion equation y=xtanB-(1/2)gx^2(VocosB)^-2 set it equal to 0. 3. Since max R=(Vo^2)/g solve for (Vo^2) and substitute. 4. Solve for X after substituting and you're done. If you need...
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    Acceleration from Vi, Vf and Distance

    Thanks 1 error to go many more to come hehe, I hope I'll get it before tomorrow
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    Acceleration from Vi, Vf and Distance

    Homework Statement 7. The engineer driving the Shinkansen (Japanese bullet train) from Tokyo to Kyoto is having a nice day until he rounds a bend and suddenly sees a slow-moving freight train on his track. Both trains are traveling west, with speeds vs and vf respectively. Of course, as...
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    Motion in two or three dimensions

    Yeah I did it the other way and is way simpler using conservation of energy, oh well now I have two ways of doing it, thanks for the help. 1. a)PE=mgh b)KE=(1/2)mv^2 2. By conservation of energy PE=KE so mgh=(1/2)mv^2 3. m divides out on both sides and you get gh=(1/2)v^2 4. Therefore...
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    Motion in two or three dimensions

    Ok I think I got it, can someone please let me know if this is right or not. This is what I did. 1.(Eq.a)h=Vt-(1/2)gt^2 and from a previous equation found (Eq.b)t=(2h/g)^(1/2) 2.From Eq.a V=[h+(1/2)gt^2]/t 3.Plugging (b) into new (a) gives V=2h/(2h/g)^(1/2) 4.Rationalizing gives...
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    Motion in two or three dimensions

    Homework Statement A projectile is being launched from ground level with no air resistance. You want to avoid having it enter a temperature inversion layer in the atmosphere a height h above the ground.(a) What is the maximum launch speed you could give this projectile if you shot it straight...
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    Equilibrium. Vectors and resultant forces.

    Thanks for the help, the wording of the question also got me confused, but here's a link to the exact wording of the question and a diagram which also got me confused wether the force was directly downward or not. http://faculty.jsd.claremont.edu/jhigdon/phys33/phys33_07_HW_1.pdf I already...
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    Equilibrium. Vectors and resultant forces.

    Homework Statement An object is at equilibrium if all the forces on it add up to zero. There's a beam which weights 124N 40degrees above the horizontal that is supported in equilibrium by a 100-N pull 30degrees above the beam and a force F at the floor. The third force on the beam is the 124-N...
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