Recent content by deryk

The question asked to solve this initial value problem (2+x^2)dy/dx = x(y+3) (2+x^2)dy/(dx*(y+3) = x dy/[(y+3)*dx]= x/(2+x^2) dy/(y+3) = x*dx/(2+x^2) S dy/(y+3) = S x/(2+x^2)*dx ln(y+3) = ? Im not sure what to do with the RHS do I do integration by parts?

Given the four points A(0,1,3), B(1,-3,-2), C(4,2,-1) and D(3,6,4) use vector methods to: (a) show these points are coplanar: I just did a determinant of AB BC and CD and got an answer of 0 so it is complanar Im don't know how to do the next 3: (b)find the equation of the plane; (c)...

How would you write z=+ or -(-1+i)^0.5 & z= + or - (2-i)^0.5 in polar and cartesian form? Thanks.

Hello, I am trying to solve (z^4-2+i)(z^2+1-i)=0 With the quadratic formula: (z^2+1-i)=0 Does a=1, b=1 & c=-1? Thanks for your time. IM meant to (a) Give answers in polar form using the principal argument; (b) Give answers in cartesian form Cartesian is (x,y) is it not...

(5x^4-6x^3+31x^2-46x-20)/(2x^5-3x^4+10x^3-14x^2+5) I got it = 1/(2x+1) + 4.75/(x-1) + -2/(x-1)^2 + 8.75(x^2+5) My working was several pages so I am not going to post it. I was wondering if any of you know if that is right? Are there any geniuses on here who can do them in there head?

How did you get from: 5^(k+1) -4(k+1) + 15 = 5^k - 4k + 15 + 4(5^k -1)

I need to prove by mathematical induction that all positive numbers of the form 5^n-4n+15 are divisible by 16 where n is a natural number(1,2,3,4,5...). So far P(1) = 5^1-4*1+15 = 16 true for P(1) AssumeP(k) is true. 5^k-4k + 15 is disible by 16. Now for P(k+1) P(k+1)=5^(k+1)...

thanks lurf lurf .I got x>2. Does anyone know if that's right?

Im trying to solve (4x-4)/(x+2)< 2x-3 I get it down to 0<(2x+1)(x-2) if x+2>0 0>(2x+1)(x-2) if x+2<0 Are these right so far? I am not sure what to do now with the product being bigger or smaller than 0. Thanks for your time.