Recent content by destroyer130

Based on this and the equation F = -d\Phi/dr. I can't visualize what is positive and negative force direction (what is positive direction). So is that just mean whenever the force between 2 molecules (+), it's repulsive; and whenever it's (-), it's attractive? Thanks for checking this out.

Thank you so much you all :). Seem like Linear Algebra (Matrices) is a good choice!

I really want to do something more of a scientist like research because my major already specify in factory and process planing. From so far I know, all natural sciences are very interrelated, at a level that I'm too afraid to ignore something :D. I always thought that Quantum Phys is hard and cool.

Hm, somehow I didn't have to learn Matrices. Which gives me pretty hard time on the Diff Eq last semester. That's true though. Although, I want to know a little bit about why more prepared in Matrices and Quantum doesn't help much for Bio and Chem E. Like from what I know in my school, Bio...

I am a sophomore majoring in Chemical Engineering. I have checked my classes requirement and seen that Chem E major doesn't need Matrices math or Quantum physics. I am wondering how so? And also, I am currently have 2 credits free for Spring semester. I am wondering should I study...

Problem Solution answer For this one, my upper bound of z in cylindrical's is sqrt(4-r^2) instead of (4-r^2). Which one is right, mine or the solution? Thanks for helping me out.

I just have a small question? What is the AcHN structure that attach to the carbon number 2 on malonate ester, especially the Amidomalonate?

Wow i didn't know that there's such technique. This is from my sample final exam about Vector Integral. Could you look at the problem i attached and tell me if there's any other way that didn't have to go through that Gaussian Integrals? Thanks a lot Dick!

This problem is about Line integral of Vector Field. I believe the equation i need to use is: \intF.dr = \intF.r'dt, with r = r(t) I try to solve it like this: C1: r1= < 1 - t , 3t , 0 > C2: r2= < 0 , 3 - 3t , t > C3: r3= < t , 0 , 1 - t > After some computation, I got stuck at the...

Okay, thanks so much for your help :)

Based on parametric equation, if x = rcosθ, y=rsinθ, then dA = r dr dθ In my homework case: dS = |ru x rv| dA = |ru x rv| r dr dθ so that why somehow there is r^1 excess? but idk what r is excess?

Oh, so why dA not equal to rdrdt in this case?

Thanks for checking this out. Here's the problem: I attempted to do it by using parametrize it into spherical coordinate. r(r,t) = (x= cost, y= sint, z=r) dS=|r_{u} x r_{v}| dA = r\sqrt{2} dA dA = rdrdt \int\intx^{2}z^{2}dS = \int\int\sqrt{2} cos^{2} r^{6} drdt I check my...

Thanks micromass :)

δx mean the denominator if taking partial derivative of f wrt x. I wonder both dx and δx equal, since they both mean infinitesimal amount of x.