Recent content by dexter90

Thank you, I was reading that the fortran functions are placed at the end, My mistake. I am sorry. I greet.

I have solid fundation in programming. Your code not woking, I was writing the same code

program iteration IMPLICIT NONE call potega(5) end iteration real function potega(a) real :: a a+2 end function potega And I have error: Error: Statement not recognised Warning: The result of FUNCTION POTEGA has never been set Warning: n a call to POTEGA from another...

program iteration real :: p IMPLICIT NONE call add(5) p=add(5) end iteration real function add(a) real :: a a+2 end function add It not working... Why?? I use PLATO IDE ( FORTRAN 95 ) I greet.

It is ok, work. I greet.

I have function: function dxdy = kkd(t,y) x=y(1); y=y(2); dxdy(1)=-0.02*x+x*x*y+0.01; dxdy(2)=0.02*x-x*x*y; next [t,y]=ode45(@kkd,[0 4],[0 10]); but is error... Where is error??

Thanks, Of course, I made mistake in write. I would like solve partial differential equation but I don't have experience. I edited my post.

Hello. I have equation: \frac{\partial T}{\partial t}-\frac{1}{2}\cdot \frac{(\partial)^2 T}{\partial x^2}=0 I calculated determinant: \Delta=(-\frac{1}{2})^2)-4\cdot 1 \cdot 0 \Rightarrow \sqrt{\Delta}=\frac{1}{2} \\ (\frac{dT}{dt})_{1}=-\frac{1}{4} \\ (\frac{dT}{dt})_{2}=\frac{1}{4} next...

Ok. I understand all, thanks you. I greet! :-)

Ok. I can add forces in the same way??

:) I have a question to this formula: -ma... Not exist - in ma=μmg. Now, it is present because force air resistance is returned in the opposite direction?? I apologize for the grammar :)

Thanks you for quickly answer. I understand, one object -> one force ( friction on the surface ). Friction is force which retard object. If on the object interacts more force's then coefficient retard is bigger, example: air resistance, then We have from formula: m\cdot a=m\cdot g\cdot μ, next...

Good Morning I am new user on Forum and I'm sorry for all mistake. I am living in Poland and My English is on the low level. My question concers friction on the objects. We have formula: T=μ \cdot N, where μ - coefficient on fraction N=m\cdot g and formula: F=m\cdot a I think that: F=T...