Recent content by dfetnum

So, there is no online copy? I would also like to read it

I'm sorry, this is really confusing. I am just going in circles now with the numbers of the charges. I am using q1/r1=(qtotal-q1)/r2. I am getting a number larger than q total

So if I find the electric potential of both spheres before they connect, then use the proportional area, I can find the amount of potential area of one of the spheres and then multiply by the radius to find the Electric field?

potential?

I don't know, electric field?

Homework Statement Two metallic spheres have radii of 19.1 cm and 11.5 cm, respectively. The magnitude of the electric field on the surface of each sphere is 3490 V/m. The two spheres are then connected by a long, thin metal wire. a) Determine the magnitude of the electric field on the...

oh wow, I didnt realize that the total work done was zero if there was no other charge to push against it. Cool, I figured out the rest. Thanks

so, what equation would that be? The one I am using still has a radius and a place for a second charge

that is my attempt at a. I need to find the potential energy from the two different charges and then add them

Homework Statement Three charges, q1, q2, and q3, are located at the corners of an equilateral triangle with side length of 1.49 m. Find the work done in each of the following cases: a) to bring the first particle, q1 = 1.33 pC, to P from infinity b) to bring the second particle, q2 = 2.99...

You need to isolate the x, so you should multiply out the exponent and rearrange the problem in order to use the quadratic equation. Edit: Actually don't isolate the x, just multiply the exponents out and group the similar exponents out. Edit 2: Hmm, its not working for me, disregard post

yes, and sorry I don't remember optics too well.

When the positive charged object is brought close to the metal rod, it attracts the opposite charge. In this case, the negative charge would be attracted to the positive charge, right? Because opposite charges (positive and negative) attract and the same charges (negative + negative, positive +...

WOWWWWWWWWWW, how could I have done that. I spent way too long on this problem. thanks!

Thanks! So first I set Fe=Fg: G*M(earth)*M(moon)/(r^2) = k*(QE)(QM)/(r^2) radius's cancel out G*M(earth)*M(moon) = k*(QE)(QM) The problem stated that the charges are equal so: G*M(earth)*M(moon) = k*2Q Then I plugged in: (6.67 x 10^-11 Nm^2 / Kg^2) * (6.0 x 10^24...