Recent content by dilasluis

That solved it! Thanks!

I'm testing a part of a code and I have a problem. After the subroutine call at line 44 (CALL ZEIGSUB), nothing is written in UNIT NRES. The other units are written correctly. Here's the code: PROGRAM TEST IMPLICIT NONE complex *16, allocatable :: KSTAR(:,:), VR(:,:), CM2(:,:) real *8...

I'm just writing equations for the sake of it... I'm not trying to solve them... And would this make sense: If I would make an average of the equation and solve for x, like this: Suppose you have: x\cos\theta - x^2 \sin^2\theta - \csc\theta\cot\theta = 0 then to find a solution to x...

I don't know if you will understand... but I want to know if any value for the angle, as long as it has a finite result, can be used to solve an equation with unknown angles. How would you solve this, for instance: x \sin \theta + \sqrt{x \cos \theta} = 0 ? Could you assume any value...

That sine actually made me think on something, even if it holds, the equation would not be valid for that particular value of \theta .

Sorry, bad choice on the sine... But imagine that you have the following equation: x \cos \theta - y(\theta) \cos^2\theta = 0 I wish to find a solution for x. What I want to know is if it is equivalent: x = y (0 \deg) = \frac{y (45 \deg) \frac{1}{2}}{\frac{1}{\sqrt{2}}} = \frac{ y...

Angle panic! When we have a relation like, for instance, f(\theta) + g(\theta) = constant where \theta is an angle, does it hold for any angle such that we can do f(0 \deg) + g (0 \deg) = 0 and we would obtain an universal result? I mean, imagine f(\theta, x) = x \sin \theta , then...

This could help, if not you, someone else: Not just kinetic

My biggest problem with this question is f(z) in both sides of the equation... and how do I change the integral from left side to the right.

z is a function of t, but not explicit, actually V_z = \frac{dz}{dt} was the relation from which we took d t = \frac{dz}{V_z} . V_z = cte

Hello! My problem is the following: Is \int_a^b f(z) dt = \int_{g(a)}^{g(b)} f(z) \frac{1}{g} dz ? \frac{dz}{dt} = g Thank you!

I solved the problem considering that the equilibrium temperature is 0ºC. The iceberg is melted and it lowers the water temperature around it to 0ºC. Anyone has any idea?

Given the molar mass of Fe and the specific heat of Sn, what is the specific heat of Fe and the molar mass of Sn in approximate values?

1. An iceberg of mass m_{ice} is melted by the ocean at temperature T_{ocean}. Knowing that the iceberg is at a temperature T_{ice} what was the volume of water needed to melt the iceberg? 2...

Thank you and by the way... That wasn't the only picture I've found... I've got other that is more explicit than the one I've pasted the link (that was just for people who didn't need to know how it looked like as much as i did)... but I'm still trying to figure out what is the diference...