Recent content by diracdelta

  1. diracdelta

    Mass m oscillations with conductivity

    Sphere of mass m, and charge q is hanged on a thread of length l in a constant gravitational field g. There is infinite horizontal conductive plan which is kept at potential 0. Find period of small oscillations of sphere. So my question is next, how do i get the force due tu charge q in Newtons...
  2. diracdelta

    Probability density function of uniform distribution

    Hmm, i see. Ok then, i get this F_{Y}(y)=P(Y\leq y)=P(x^{1/2}+1\leq y)=P(x\leq (y+1)^{2}) =F_{x}(y+1)^{2} \\ f_{X}(x)=F_{X}'(y+1)^{2}=f_{X}(y+1)^{2}* \left | \frac{d}{dy} (y+1)^{2})\right |=f_{X}(y+1)^{2})*2y \\ f_{Y}(y)=\begin{cases} 2y & \text{ if } 1\leq x\leq 2\\ 0 & \text{ else} \end{cases}...
  3. diracdelta

    Probability density function of uniform distribution

    Homework Statement Random variable X is uniformly distributed on interval [0,1]: f(x)=\begin{cases} 1 & \text{ if } 0\leq x\leq 1\\ 0 & \text{ else} \end{cases} a) Find probability density function ρ(y) of random variable Y=\sqrt{X} +1 I tried like this. Is it good, if no why not...
  4. diracdelta

    4 balls and 4 cells probabillity

    Ok. Thanks for help! I noticed. By the way, could someone help me with PeroK's suggestion? I have no clue what other acces should I approach this problem with. Only thing that pops into my mind is number of number of ways "A" occurs / number of all possible ways.
  5. diracdelta

    4 balls and 4 cells probabillity

    Alright. So I only choose one out of 4 cells, which yields p= 4/256 As far as this, 4 choose 2 (cells) and (4 choose 2) for balls?
  6. diracdelta

    4 balls and 4 cells probabillity

    Homework Statement Four balls are distributed randomly and independently into 4 cells. What is probability that: a) In every cell there is exactly one ball? b) All four balls be in one cell? c)Two balls in one cell ( any) , other two balls in other cell (any)? (assume that the balls are...
  7. diracdelta

    Conditional probability problem - good solution?

    I am not sure I understand exactly. I am supposed to find factor which preserves P(H1|~H4) + P(H2|~H4) + P(H3|~H4) = 1 and later on multiply every P(A|H1) with it. What does tilda ~ means?
  8. diracdelta

    Conditional probability problem - good solution?

    Homework Statement We have 6 new and 4 used products in a box. We draw randomly 2 products and used them for a while. then return them back into the box. After that, again we draw 2 products. a) What is probability that at least one is new? b) What is probability that at least one is new if we...
  9. diracdelta

    How Do You Solve These Delegation Selection Problems in Combinatorics?

    No. So basicly I have this: Five slots, where one is determined in advance to be women. Lets say its first slot. We can choose that women in 7 ways, so is this ok 7[\binom{6}{1}\binom{4}{3} + \binom{6}{2}\binom{4}{2} + \binom{6}{3}\binom{4}{1}] +\binom{6}{5}
  10. diracdelta

    How Do You Solve These Delegation Selection Problems in Combinatorics?

    Hmm, I tought something wrong. But i got it now. Thhanks !
  11. diracdelta

    How Do You Solve These Delegation Selection Problems in Combinatorics?

    I see that. I also have to do the same for men? One more thing. Do I then sum 1 women and 4 men + ... 4 men & 1 women?
  12. diracdelta

    How Do You Solve These Delegation Selection Problems in Combinatorics?

    You are right, its accident. first term shouldn't be there. ( expr. c) d) says that we have determined that one person is definitely women, other 4 can be both men and women. - So, first we can choose women in 7 ways. but how do i get other four ? By the way, a) and b) are correct?
  13. diracdelta

    How Do You Solve These Delegation Selection Problems in Combinatorics?

    Homework Statement Out of 7 women and 4 men you need to choose delegation. On how many ways you can choose delegation that consist of: a) five people - 3 women and 2 men b)any number of people, but with equal number of men and women c) five people with at least 3 women d) five peope where one...
  14. diracdelta

    Quadratic form and diagonalization

    Av1=λ1v1 And Av2=λ2v2 While v1 and v2 are ||v1|| and |v2|| So Q(x) = 1* η12 + +6η22 η1=1*(ε1 - ε2)*(1/21/2 η2= 6*(ε1 - 1/2 ε2)*(51/2/2) And Q(x) = λ1η12 + λ2η22
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