Hi Blechman,
Thank for your reply.
First of all, I was studying and thinking about my initial question and maybe I got the answer.
May I say that R-symmetry is spontaneously broken if and only if any R-charged superfield get a non-vanishing VEV?
Another question:
In fact...
Spontaneously broken R-symmetry is a sufficient condition for spontaneously supersymmetry breaking.
My question is: What is a spontaneously R-symmetry breaking?
I have a technical question and at the time being I can't ask it to a professor. So, I'm here:
If I try to quantize the vector field in the Coulomb gauge (radiation gauge)
A_0(x)=0,\quad \vec\nabla\cdot\vec A=0.
by imposing the equal-time commutation relation...